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noname [10]
3 years ago
8

A new car is purchased for 16500 dollars. The value of the car depreciates at 5.75% per year. What will the value of the car be,

to the nearest cent, after 5 years?
Mathematics
1 answer:
Gnom [1K]3 years ago
7 0
A=16500(1-0.0575)^5
A=16,500×(1−0.0575)^(5)
A=12,271.30
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10 lbs of apples will cost $55 

How? Well...

First, you would need to find the unit rate, which is 5.5
You find the unit rate by simply dividing 33 by 6. Next, after you found your unit rate, you're going to multiply that by 10. We now know that 10 x 5.5= 55. Therefore, you will need $55 for 10 lbs of apples.
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One-Half the difference of a number and 15
slega [8]

Answer:

x - 15 ÷ 2

Step-by-step explanation:

Since it wants you to find the half of your answer after you find the difference, be sure to leave the two at the end of your equation. With that said, let's move into finding out what "the difference of a number and fifteen is". Whenever they tell you 'a number', it means they want you to put a variable, such as x, since you do not know the number and it could be any number. Now, the "difference" of something usually means...you guessed it, subtraction! Now that you've decoded your equation, you now know it means that x - 15 is the first part, and you can now put the one half right after it.

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5 0
3 years ago
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100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!
Volgvan

Using weighed averages, it is found that:

  1. The final grade is 91.
  2. The final grade is 66.8.
  3. The higher grade would be 79.55, with the second grading scheme.
  4. On average, she sold $48,280 per day.
  5. On average, she makes $12.5 per hour.

---------------------------------------

To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

  • Grade of 91, with a weight of 67%.
  • Grade of 91, with a weight of 33%.

Thus:

F = 91\times0.67 + 91\times0.33 = 91

The final grade is 91.

---------------------------------------

Question 2:

  • Grade of 83, with a weight of 40%(highest grade).
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  • Grade of 52, with a weight of 30%.

Thus:

F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

  • 75 with a weight of 25%.
  • 80 with a weight of 10%.
  • 85 with a weight of 40%.
  • 62 with a grade of 25%.

Thus:

F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25

---------------------------------------

With teacher 2:

  • 75 with a weight of 15%.
  • 80 with a weight of 10%.
  • 85 with a weight of 60%.
  • 62 with a weight of 15%.

Thus:

F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

  • Average of $36,432, with a weight of \frac{3}{3+10} = \frac{3}{13}
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Thus:

A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

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Thus:

A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

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\dfrac{h}{5}>1\\
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