<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
Answer:
345,456
Step-by-step explanation:
The value of 3 in 135,864 is 30,000.
We want to write a number that is ten times 30,000.
We could write any other number in which the value of 3 is 300,000.
There are infinitely many numbers that we can write.
Some examples are:
345,456
1,315,445
5,354,456
and so on and so forth.
So, when you divide by a fraction, you are basically multiplying by the reciprocal of said fraction. Ergo:
6/8 * 9/78 = 54 / 624
Answer:
Faris' arrival time = 3:30 pm + 3 h 54 mnt = 7:24 pm
Step-by-step explanation:
Driving distance between Manchester to London = 195 miles
Coach left Manchester = 3.30 pm
Average speed of coach = 50 mph
Total time taken by the coach to reach the Manchester to London = 195÷50 = 3.9 h
0.9 h = 0.9×60 mnt = 54 mnt
Now,
3.9 h = 3 h 54 mnt
Hence Faris' arrival time in London = 3.30 pm + 3 h 54 mnt = 7.24 pm
Answer:
The y coordinates become the opposite of what they already are.
Step-by-step explanation:
Example: (3,2) -> (3,-2). (-4, -7)-> (-4,7)
