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Temka [501]
3 years ago
15

Liner equations please help with answer!

Mathematics
1 answer:
svetlana [45]3 years ago
6 0

Answer:

n = - \frac{4}{7}

Step-by-step explanation:

Given

\frac{2}{3} (1 + n) = - \frac{1}{2} n

Multiply both sides by 6 ( the LCM of 3 and 2 ) to clear the fractions

4(1 + n) = - 3n ← distribute left side

4 + 4n = - 3n ( add 3n to both sides )

4 + 7n = 0 ( subtract 4 from both sides )

7n = - 4 ( divide both sides by 7 )

n = - \frac{4}{7}

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sergij07 [2.7K]

Answer:

The answer is C. 6.4 X 8 in

Step-by-step explanation:

If the scale factor from the original to the trimmed photo is 5:4

The statement above just means the scale of the old dimension is 5 while the scale of the new dimension is 4.

To get the new dimensions, multiply each of the old dimensions by 4/5

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Write an equivalent expression for 4(3a+7)+3 (2a+5) if a=5, is the the solution to both expressions the same
Levart [38]
<span>Alternative</span>
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4 0
2 years ago
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An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden
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Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

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The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277

Then, we can calculate the z-statistic as:

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As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

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The  95% confidence interval for the population mean is (0.0556, 0.1644).

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