Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Answer: -x^2 + 15x
Step-by-step explanation:
Answer:
infinite
Step-by-step explanation:
Answer:
I'll sub to u if u sub to me
Answer: x = 3
Step-by-step explanation:
First you need to start by adding positive 4x to both sides since the 4x is a negative. 4x + (-7x) = -3x. Then it is just simply -3x+2 = -7. Since 2 is a positive number subtract both both sides by 2. Then you should get -3x = -9. Then divide both sides by -3 and the answer is x = 3.