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vovangra [49]
3 years ago
8

For their CD collections, Alan, Tom, and Barbara have a total of 52 CD’s. If Barbara had 6 more, then she would have as many a

s both of the boys together. Tom has three more CD’s than Alan. How many CD’s does each of the three have?
Alan has 13 CDs, Tom has 23 CDs, Barbara has 16 CDs

Alan has 23 CDs, Tom has 16 CDs, Barbara has 13 CDs

Alan has 13 CDs, Tom has 16 CDs, Barbara has 23 CDs

Alan has 16 CDs, Tom has 13 CDs, Barbara has 23 CDs
Mathematics
1 answer:
Anestetic [448]3 years ago
8 0
<span>its C. Alan has 13 CDs, Tom has 16 CDs, Barbara has 23 CDs !</span>
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Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $35 and same-day tickets $30 c
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Answer:

The number of same-day tickets sold is 15

The number of advance ticket sold is 20

Step-by-step explanation:

Given as :

The cost of each Advance ticket = $35

The cost of each same-day ticket = $30

The total cost of the tickets sold = $1150

The total number of tickets sold = 35

Let The number of advance ticket sold = a

And The number of same-day ticket sold = s

Now, According to question

The total number of tickets sold =The number of advance ticket sold + The number of same-day ticket sold

I.e a + s = 35                   .....A

The total number of tickets sold = The cost of each Advance ticket × The number of advance ticket sold + The cost of each same-day ticket × The number of same-day ticket sold

I.e $35 a + $30 s = $1150

or, 35 a + 30 s = 1150               .......B

Now, solving eq A and B

35 × ( a + s) - ( 35 a + 30 s ) = 35 × 35 - 1150

or, ( 35 a - 35 a ) + ( 35 s - 30 s ) = 1225 - 1150

or, 0 + 5 s = 75

∴  s = \frac{75}{5}

I.e s = 15

So, The number of same-day tickets sold = s = 15

Put the value of s in Eq A

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I.e a = 20

So, The number of advance ticket sold = a = 20

Hence The number of same-day tickets sold is 15

And  The number of advance ticket sold is 20   Answer

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