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3 years ago

HELP ASAP I will mark brainliest

Chemistry

2 answers:

nasty-shy [4]3 years ago

5 0

Answer:

10623.0

Explanation:

Because 3541 is speed per hour

You need to find 3 hours

so multiply 3541 x 3

3541 x 3 = 10623

docker41 [41]3 years ago

3 0

Answer: The last one I think

Explanation:

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During the formation of a solution, which step is always an exothermic process? a. the separation of solute particles from one a

Galina-37 [17]

ccccccccccccccccccccccccccccccccccc

3 0

3 years ago

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How much heat energy in megajoules is neede to convert 7kilograms of ice at negative 9 degrees to water at 0 degrees celsius

den301095 [7]

Heat_1: Get the ice to 0 degrees

Convert 7 kg to grams

7 kg [1000 grams / 1 kg] = 7000 grams

Heat needed to get the the ice from - 9 to 0

deltat = 0 - -9 = 9 degrees

m = 7000 grams

c = 2.1 joules/gram

Heat_1 = m*c*deltat

Heat_1 = 7000 * 2.1 * 9

Heat_1 = 132,300 joules

Heat_2: Melt the ice.

There is no temperature change. The formula is 333 j/gram

Formula: H = mass * constant

H = 7000 g * 333 J / gram

H = 2331000 joules

Heat_3: Total amount of Joules needed.

2331000 + 132300 = 2 463 300 joules

Convert to Megajoules

2 463 300 joules * 1 megajoule / 1000000 = 2.63 megajoules.

8 0

3 years ago

12 = 3X X = <br> 7X = 57 X = <br> 11X = 27.7 X =

dybincka [34]

Answer:
1. $x=4$
2. $x=\frac{57}{7}$
3. $x=\frac{27.7}{11}$

Explanation:

Given the following questions:

$12=3x$
$7x=57$
$11x=27.7$

In order to find the answers to these questions, we have to recognize that in order to isolate the variable we need to divide on both sides.

Question one:
$12=3x$
$\frac{3x}{3} =\div3$
$12\div3=4$
$x=4$

Question two:
$7x=57$
$\frac{7x}{7} =\div7$
$57\div7=8.14285714=\frac{57}{7}$
$x=\frac{57}{7}$

Question three:
$11x=27.7$
$\frac{11x}{11} \div11$
$27.7\div11=2.51818182=\frac{27.7}{11}$
$x=\frac{27.7}{11}$

Hope this helps.

3 0

2 years ago

What happens to the ionizing rate if the steps of ionizing polyprotic acid increases?

Tanzania [10]

Answer:

<h3>An acid that contains more than one ionizable proton is a polyprotic acid. The protons of these acids ionize in steps. The differences in the acid ionization constants for the successive ionizations of the protons in a polyprotic acid usually vary by roughly five orders of magnitude.</h3>

5 0

3 years ago

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How many liters of gas will be in the closed reaction flask when 36.0L of ethane (C2H6) is allowed to react with 105.0L of oxyge

Ivan

Answer:- Volume of the gas in the flask after the reaction is 156.0 L.

Solution:- The balanced equation for the combustion of ethane is:

$2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)$

From the balanced equation, ethane and oxygen react in 2:7 mol ratio or 2:7 volume ratio as we are assuming ideal behavior.

Let's see if any one of them is limiting by calculating the required volume of one for the other. Let's say we calculate required volume of oxygen for given 36.0 L of ethane as:

$36.0LC_2H_6(\frac{7LO_2}{2LC_2H_6})$

= 126 L $O_2$

126 L of oxygen are required to react completely with 36.0 L of ethane but only 105.0 L of oxygen are available, It means oxygen is limiting reactant.

let's calculate the volumes of each product gas formed for 105.0 L of oxygen as:

$105.0LO_2(\frac{4LCO_2}{7L O_2})$

= 60.0 L $CO_2$

Similarly, let's calculate the volume of water vapors formed:

$105.0L O_2(\frac{6L H_2O}{7L O_2})$

= 90.0 L $H_2O$

Since ethane is present in excess, the remaining volume of it would also be present in the flask.

Let's first calculate how many liters of it were used to react with 105.0 L of oxygen and then subtract them from given volume of ethane to know it's remaining volume:

$105.0LO_2(\frac{2LC_2H_6}{7LO_2})$

= 30.0 L $C_2H_6$

Excess volume of ethane = 36.0 L - 30.0 L = 6.0 L

Total volume of gas in the flask after reaction = 6.0 L + 60.0 L + 90.0 L = 156.0 L

Hence. the answer is 156.0 L.

5 0

3 years ago