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AfilCa [17]
3 years ago
14

A certain first-order reaction (A→products) has a rate constant of 9.00×10−3 s−1 at 45 ∘C. How many minutes does it take for the

concentration of the reactant, [A], to drop to 6.25% of the original concentration?
Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
5 0

Answer:

27.8 minutes

Explanation:

The reaction follows a first order

Rate = k[A] = change in concentration/time

k = 9×10^-3s^-1

Let the original concentration of A be y

Concentration of A at time t = 6.25% × y = 0.0625y

Change in concentration = y - 0.0625y = 0.9375y

0.009 × 0.0625y = 0.9375y/t

t = 0.9375y/0.0005625y = 1666.7sec = 1666.7/60 = 27.8 minutes

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An electron initially in a 4p state decays to a lower energy state. which energy state is forbidden?
kogti [31]

The state of energy that is forbidden is 2p orbital. The correct option is b).

<h3>What is the energy state of electrons?</h3>

The energy state of an electron depends upon the presence of the electron on the orbitals. Lower the energy they will be in the lower orbital. When they get higher energy they move to the higher orbital.

By using the Selection Rules for Electron Transitions

1.) ?l = +/- 1 and

2.) ?m = 0, +/- 1

The conservation of angular momentum is required by these laws. A photon's inherent angular momentum is 1. As 4p is higher than 2p and the electron is lowering its energy. So, it will go down to 2p orbital.

Thus, the correct option is b). 2p orbital.

The question is incomplete. Your full question is given below:

a) 3d

b) 2p

c) 1s

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3 0
1 year ago
Which statement correctly describes electrochemical cells?
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Answer: C. Electrochemical cells involve oxidation-reduction reactions.

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3 0
3 years ago
Which type of equilibrium exists in a sealed flask containing Br2(ℓ) and Br2(g) at 298 K and 1.0 atm?(1) static phase equilibriu
nikdorinn [45]
"(2) static solution equilibrium" is the type of equilibrium that exists in a sealed flask containing Br2(ℓ) and Br2(g) at 298 K and 1.0 atm. 
7 0
3 years ago
-1.42, 3, 32.5%, √4, 2³, −0.375, 3/8 as a decimal least to greatest
nignag [31]

Answer:

-1.42, -0.375, 32.5% (.325), 3/8 (.375), √4 (2.0), 3 (3.0), 2³ (8.0)

8 0
1 year ago
A chemist prepares a solution of silver perchlorate by measuring out of silver perchlorate into a volumetric flask and filling t
djverab [1.8K]

Complete Question:

A chemist prepares a solution of silver (I) perchlorate (AgCIO4) by measuring out 134.g of silver (I) perchlorate into a 50.ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the silver (I) perchlorate solution. Round your answer to 2 significant digits.

Answer:

13 mol/L

Explanation:

The concentration in mol/L is the molarity of the solution and indicates how much moles have in 1 L of it. So, the molarity (M) is the number of moles (n) divided by the volume (V) in L:

M = n/V

The number of moles is the mass (m) divided by the molar mass (MM). The molar mass of silver(I) perchlorate is 207.319 g/mol, so:

n = 134/207.319

n = 0.646 mol

So, for a volume of 50 mL (0.05 L), the concentration is:

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M = 12.92 mol/L

Rounded to 2 significant digits, M = 13 mol/L

7 0
3 years ago
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