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wariber [46]
2 years ago
13

12 = 3X X = 7X = 57 X = 11X = 27.7 X =

Chemistry
1 answer:
dybincka [34]2 years ago
3 0

Answer:
1. x=4
2.x=\frac{57}{7}
3.x=\frac{27.7}{11}

Explanation:

Given the following questions:

12=3x
7x=57
11x=27.7

In order to find the answers to these questions, we have to recognize that in order to isolate the variable we need to divide on both sides.

Question one:
12=3x
\frac{3x}{3} =\div3
12\div3=4
x=4

Question two:
7x=57
\frac{7x}{7} =\div7
57\div7=8.14285714=\frac{57}{7}
x=\frac{57}{7}

Question three:
11x=27.7
\frac{11x}{11} \div11
27.7\div11=2.51818182=\frac{27.7}{11}
x=\frac{27.7}{11}

Hope this helps.

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Answer:

B) PO2

Explanation:

first solve empirical formula

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1.5. 3.0

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1. :. 2

Empirical formula=PO2

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1) You need to use the atomic mass of copper.


You can find it in a periodic table. It is 63.546 amu.


2) The atomic mass is the weigthed mass of the different isotopes.


This is, the atomic mass of one element is the atomic mass of each isotope times its corresponding abundance:


=> atomic mass of the element = abundance isotope 1 * atomic mass isotope 1 + abundance isotope 2 *  atomic mass isotope 2 + ....+abundance isotope n * atomic mass isotope n.


3) The statement tells there are two isotopes so the abundance of one is x and the abundance of the other is 1 - x


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Answer:


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