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torisob [31]
3 years ago
14

PLZ HELP ME I BEG UUUUU

Mathematics
2 answers:
nalin [4]3 years ago
7 0

Answer:

43.96

Step-by-step explanation:

14 x 3.14 = 43.96

7 is the radius but 14 is the like line and to find it you add 7 plus 7 (aka the other half) and multiply it by 3.14 thus the answer is

43.96

Nookie1986 [14]3 years ago
3 0

Answer:

B

Step-by-step explanation:

C = d x pi

Since the radius is half of the diameter, we have to multiply 7 and 2 which would give us 14. After that, we multiply 14 and 3.14 which gives us 43.96 in.

You might be interested in
Courtney would like to buy a new ca in 4 years. It is estimated that a new car will cost her 25,000 and that she will get 13,000
KiRa [710]

4 years=48 months

A new car costs 25,000, but she will get 13,000 for her used car as long as she takes good car of it. If she takes good care of her used car and gets 13,000 for it, she will only need to save 12,000 total. We can divide 12,000 by 48 to find out how much Courtney should save minimum each month to afford her new car. 12,000/48=250

You can check to see if this is correct by multiplying 48*250=12,000. Paying 250 for each month of the 48 months will equal the $12,000 that Courtney needs.

Courtney needs to save at least $250 per month to afford her new car in 4 years.

I hope this helps :)

3 0
4 years ago
if anyone could help me to figure out whether or not this is correct i would appreciate that. thank you :)
hram777 [196]
450 with an exponent of 3 equals -1425 so I think u are right
3 0
3 years ago
Read 2 more answers
What are the vertical asymptotes of f(x) = 10/ x^2 - 1
Veronika [31]

Vertical asymptotes ares found where the function is undefined.  f(x) is undefined when the denominator equals zero:

x^2-1=0

<em>*Add 1 to both sides*</em>

x^2=1

<em>*Take the square root of both sides*</em>

x=+/-1

There are vertical asymptotes at x=-1 and x=1.

Hope this helps!!

8 0
4 years ago
I need help please it’s ASAP
malfutka [58]

The interquartile range of the data is equal to 2.18.

<h3>What is an interquartile range?</h3>

The interquartile range is a measure of where a data set's "middle fifty" is located. Whereas a range is a measure of where the start and end of a set are, an interquartile range is a measure of where the majority of the values are.

Given data is { 1.56,1.77,2.22,2.35,2.45,2.77,3.26,4.35,5.23,6.02}.

The upper limit is, and the median is 2.22.

{ 1.56,1.77,<u>2.22</u>,2.35,2.45,2.77}

The lower limit is, and the median is 4.35.

{2.77,3.26,<u>4.35</u>,5.23,6.02}

The interquartile range will be calculated as,

IQR = 4.35 - 2.22

IQR = 2.18

To know more about interquartile range follow

brainly.com/question/21270410

#SPJ1

5 0
1 year ago
the price of a ps5 is $500 but it is sold out in stores. You can purchase one on ebay for $800. What is the percent change of th
statuscvo [17]

Answer:

beinggreat78~here~to~help!

The price increased by %60. Why? Because 160% of 500 is 800, so that must mean the percent only increased by 60.

8 0
2 years ago
Read 2 more answers
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