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MaRussiya [10]
3 years ago
10

Use the diagram to complete the statement. m∠ECF = degrees

Mathematics
1 answer:
alexdok [17]3 years ago
5 0

Answer:

36.86989765

Step-by-step explanation:

As Angle GBC = Angle CDF = 45, so CF = CD as it is an isosceles right triangle  , then as sin(45) = 1/root(2), so CF = 12, then tan(angle ECF) = FE/CF = 9/12, then angle ECF = tan^-1 (9/12) = 36.86989765.

If it is helpful, plz give me Brainliest.

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Answer:

60% Hope this helped! :)

Step-by-step explanation:

3 0
3 years ago
(бх -Зу = 6<br> (2x-y=-5
BabaBlast [244]

Answer:

6-

Step-by-step explanation:

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3 0
3 years ago
at the beginning of a chemistry experiment the volume of liquid in a container was 4 milliliters. during the experiment the volu
Mrac [35]

Answer:

2.0

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3 0
3 years ago
If log2 5 = k, determine an expression for log32 5 in terms of k.
lukranit [14]

Answer:

log_3_2(5)=\frac{1}{5} k

Step-by-step explanation:

Let's start by using change of base property:

log_b(x)=\frac{log_a(x)}{log_a(b)}

So, for log_2(5)

log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)

Now, using change of base for log_3_2(5)

log_3_2(5)=\frac{log(5)}{log(32)}

You can express 32 as:

2^5

Using reduction of power property:

log_z(x^y)=ylog_z(x)

log(32)=log(2^5)=5log(2)

Therefore:

log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)

As you can see the only difference between (1) and (2) is the coefficient \frac{1}{5} :

So:

\frac{log(5)}{log(2)} =k\\

log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k

6 0
3 years ago
1. Gavin and Seiji both worked hard over the summer. Together, they earned a total of $425. Gavin earned $25 more than Seiji. Ho
Gre4nikov [31]
Let x = the amount that Seini earned
Then x + 25 = the amount that Gavin
The amount Gavin earned would also = 425 - x (your directions asked you to have 2 equations.)
Together they earned 425:
x + (x + 25) = 425
2x + 25 = 425
2x = 400
Now divide both sides by 2 to find x.

Use all of this data to satisfy the directions.
8 0
3 years ago
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