Question

a stone is thrown vertically upwards with a velocity of 20 m per second what will be its velocity when it reaches a height of 10.2 m​

Answer 1

Answer:

Explanation:

Here's the info we have:

initial velocity is 20 m/s;

final velocity is our unknown;

displacement is -10.2 m; and

acceleration due to gravity is -9.8 m/s/s. Using the one-dimensional equation

v² = v₀² + 2aΔx and filling in accordingly to solve for v:

$v=\sqrt{(20)^2+2(-9.8)(-10.2)}$  Rounding to the correct number of sig fig's to simplify:

$v=\sqrt{400+2.0*10^2}$ to get

v = $\sqrt{600}=20\frac{m}{s}$ If you don't round like that, the velocity could be 24, or it could also be 24.5 depending on how your class is paying attention to sig figs or if you are at all.

So either 20 m/s or 24 m/s