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Colt1911 [192]
3 years ago
8

To use Faraday's law for this problem, you will need to construct a suitable loop, around which you will integrate the electric

field. In which plane should the loop lie to get a nonzero electric field line integral and a nonzero magnetic flux?
a. xy
b. yz
c. zx
Physics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

a. xy

Explanation:

The Faraday's law of induction can be used to express the relationship between the electric field line integral and the magnetic flux rate change in a closed loop. In order to ensure that the relationship between the two variables is equivalent to zero, the integration should be conducted on the xy plane. The correct option is option a.

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Explanation:

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Smialarities between kinetic friction and static friction?
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Kinetic and static friction are both resistive forces

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The steps in the heating of a metal seat in a park are listed below: Step 1: Heat travels from the sun to Earth Step 2: Heat tra
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The steps in the heating of a metal seat in a park are:

Step 1: Heat travels from the sun to Earth

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3 years ago
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Residential building codes typically require the use of 12-gauge copper wire (diameter 0.205 cm) for wiring receptacles. Such ci
Alecsey [184]

Given Information:  

Current = I = 20 A

Diameter = d = 0.205 cm = 0.00205 m

Length of wire = L = 1 m

Required Information:  

Energy produced = P = ?

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P = 2.03 J/s

Explanation:  

We know that power required in a wire is

P = I²R

and R = ρL/A

Where ρ is the resistivity of the copper wire 1.68x10⁻⁸ Ω.m

L is the length of the wire and A is the area of the cross-section and is given by

A = πr²

A = π(d/2)²

A = π(0.00205/2)²

A = 3.3x10⁻⁶ m²

R = ρL/A

R = 1.68x10⁻⁸*(1)/3.3x10⁻⁶

R = 5.09x10⁻³ Ω

P = I²R

P = (20)²*5.09x10⁻³

P = 2.03 Watts or P = 2.03 J/s

Therefore, 2.03 J/s of energy is produced in 1.00 m of 12-gauge copper wire carrying a current of 20 A

8 0
3 years ago
When water is boiled under a pressure of 2.00atm, the heat of vaporization is 2.20×106J/kg and the boiling point is 120∘C. At th
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Answer:

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m = Mass of water = 1 kg

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Work done in an isobaric system is given by

W=-P\Delta V\\\Rightarrow W=-2\times 101325\times (1\times 10^{-3}-0.824)\\\Rightarrow W=166780.95\ J

Work done is 166780.95 J

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Heat is given by

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The increase in internal energy of the water is 2033219.05 J

6 0
3 years ago
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