Answer:
0.00225 N/m
Explanation:
Parameters given:
Current in first wire, I(1) = 15A
Current in second wire, I(2) = 15A
Distance between two wires, R = 1cm = 0.01m
The force per unit length between two current carrying wires is:
F/L = μ₀I(1)I(2)/2πR
μ₀ = 4π * 10^(-7) Tm/A
F/L = [4π * 10^(-7) * 15 * 15] / (2π * 0.01)
F/L = 2.25 * 10^(-3) N/m or 0.00225 * 10^(-3) N/m
Answer: 7.723s
Explanation:
given data:
initial velocity = 7.56 m/s.
friction = 0.0695.
change in velocity = 2.32 m/s
<u><em>Solution:</em></u>
Answer:
a wedge.
Explanation:
it moves when you apply force to one end of the wedge.
Answer:
0.0016 T
Explanation:
Parameters given:
Diameter of wire = 5 mm = 0.005 m
Radius of wire, R = 0.0025 m
Number of turns, N = 200
Current through the wire, I = 0.10A
The magnitude of the magnetic field is given as:
B = (u₀NI) / (2πR)
Where u = magnetic permeability of free space.
B = (1.257 * 10⁻⁶ * 200 * 0.1) / (2 * π * 0.0025)
B = 0.0016 T
The magnitude of the Magnetic field is 0.0016 T.
Answer:
Explanation:
To solve this problem we can use the Gauss' Theorem
Hence, we have:
where QN is the total net charge inside the Gaussian surface, r is the point where we are going to compute E and ε0 is the dielectric permitivity. For each value of r we have to take into account what is the net charge inside the Gaussian surface.
a) r=4.80m (r>R2)
QN=+2.50 μC+2.70 μC = 5.2 μC
b) r=0.70m (R1<r<R2)
QN=+2.50 μC
c) r=0.210 (r<R1)
Inside the spherical shell of radius R1 the net charge is zero. Hence
E=0N/C
- For the calculation of the potential we have
Thus, we compute the potential by using the net charge of the Gaussian surface
d) r=0.210 (r<R1)
Inside the spherical shell the net charge is zero, thus
E=0N/C
e) r=1.40m (R1<r<=R2)
In this case we take the net charge from the first spherical shell
QN=+2.50 μC
f) r=0.70m
QN=+2.50 μC
V=3.164*10^{4}Nm/C
g) r=0.52
QN=0
V=0
h) r=0.2
QN=0
V=0
HOPE THIS HELPS!!