To use Faraday's law for this problem, you will need to construct a suitable loop, around which you will integrate the electric
1 answer:
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Answer:
(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East
(b) When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West
Explanation:
Given;
a force vector points due east, = 140 N
let the second force =
let the resultant of the two vectors = F
(a) When the resultant force is pointing along east line
the second force must be pointing due east
(b) When the resultant force is pointing along west line
the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.
Answer:
9.22 s
Explanation:
One-quarter of a turn away is 1/4 of 2π, or π/2 which is approximately 1.57 rad
Let t (seconds) be the time it takes for the child to catch up with the horse. We would have the following equation of motion for the child and the horse:
For the child:
For the horse:
For the child to catch up with the horse, they must cover the same angular distance within the same time t:
t = 25.05 or t = 9.22
Since we are looking for the shortest time we will pick t = 9.22 s