Displacement can be defined as the overall change in the position of the object. The displacement of the car in 5 hrs is 0 km.
Displacement:
It is a vector quantity that is defined as the overall change in the position of the object.
The formula for displacement is:
![s = s_f-s_i](https://tex.z-dn.net/?f=s%20%3D%20s_f-s_i)
Where,
- total displacement
- final position
- initial position
In the given graph:
- Car displaces 15 km in 2 hrs
- Car displaces 20 km in 4 hrs.
- The car moves back to the initial position in 5 hrs.
Therefore, the displacement of the car in 5 hrs is 0 km.
Learn more about Displacement:
brainly.com/question/10919017
a) 6.25 rad/s
The law of conservation of angular momentum states that the angular momentum must be conserved.
The angular momentum is given by:
![L=I\omega](https://tex.z-dn.net/?f=L%3DI%5Comega)
where
I is the moment of inertia
is the angular speed
Since the angular momentum must be conserved, we can write
![L_1 = L_2\\I_1 \omega_1 = I_2 \omega_2](https://tex.z-dn.net/?f=L_1%20%3D%20L_2%5C%5CI_1%20%5Comega_1%20%3D%20I_2%20%5Comega_2)
where we have
is the initial moment of inertia
is the initial angular speed
is the final moment of inertia
is the final angular speed
Solving for
, we find
![\omega_2 = \frac{I_1 \omega_1}{I_2}=\frac{(2.25 kg m^2)(5.00 rad/s)}{1.80 kg m^2}=6.25 rad/s](https://tex.z-dn.net/?f=%5Comega_2%20%3D%20%5Cfrac%7BI_1%20%5Comega_1%7D%7BI_2%7D%3D%5Cfrac%7B%282.25%20kg%20m%5E2%29%285.00%20rad%2Fs%29%7D%7B1.80%20kg%20m%5E2%7D%3D6.25%20rad%2Fs)
b) 28.1 J and 35.2 J
The rotational kinetic energy is given by
![K=\frac{1}{2}I\omega^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7DI%5Comega%5E2)
where
I is the moment of inertia
is the angular speed
Applying the formula, we have:
- Initial kinetic energy:
![K=\frac{1}{2}(2.25 kg m^2)(5.00 rad/s)^2=28.1 J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D%282.25%20kg%20m%5E2%29%285.00%20rad%2Fs%29%5E2%3D28.1%20J)
- Final kinetic energy:
![K=\frac{1}{2}(1.80 kg m^2)(6.25 rad/s)^2=35.2 J](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7D%281.80%20kg%20m%5E2%29%286.25%20rad%2Fs%29%5E2%3D35.2%20J)
Answer:
Emissions per second = 0.36
Explanation:
Please find the attached question
Solution
Given
Let X be the rate of background emission.
X = B/t
Where B = 36
And t = 100
X = 36/100 = 0.36
Answer:
Our estimate not done correctly because the width was unrealistic.
Explanation:
Given that,
Length = 6 m
Width = 0.5 m
We need to calculate the area of rectangular floor
Using formula of area
![A=l\times w](https://tex.z-dn.net/?f=A%3Dl%5Ctimes%20w)
Where, l = length
w= width
Put the value into the formula
![A=6\times0.5](https://tex.z-dn.net/?f=A%3D6%5Ctimes0.5)
![A=3\ m^2](https://tex.z-dn.net/?f=A%3D3%5C%20m%5E2)
We need to find why this estimate not done correct
Using given data
We can say that,
We assume width was unrealistic.
The length of room is 6 m.
We know that,
![1\ m=3.28\ feet](https://tex.z-dn.net/?f=1%5C%20m%3D3.28%5C%20feet)
So, the length would be 20 feet.
The width of room is 0.5 m.
The width of room would be 1.64 feet.
So, the area will be
![A=20\times1.64](https://tex.z-dn.net/?f=A%3D20%5Ctimes1.64)
![A=32.8\ feet^2](https://tex.z-dn.net/?f=A%3D32.8%5C%20feet%5E2)
Hence, Our estimate not done correctly because the width was unrealistic.
Answer:
All are not true.
Explanation:
Sound needs medium to travel.
sound speed is fastest in solids.