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Georgia [21]
2 years ago
13

While driving down his street one evening, Jonah notices that his neighbor has laid out an electric fan for the garbage to pick

up the next morning. Jonah stops and has a look at the fan; it seems to be perfectly fine, so he takes it home with him. The fan would most likely be considered___________
Physics
2 answers:
zimovet [89]2 years ago
7 0

Answer:

<h2>C. abandoned property.</h2>

Explanation:

Options for this question are:

A. lost property.

B. mislaid property.

C. abandoned property.

D.None of these are correct.

Abandoned property refers to an asset that it doesn't have an owner after years of inactivity. In real state, the property would be owned by the state. However, this case is simpler, because the neighbour just threw away the fan, and Jonah picked it up from the garbage. Literally, the neighbour abandoned the article.

On the other hand, other options don't apply, because the fan is not a mislaid property, it's not missing from its owner, it wasn't lost.

Therefore the correct answer is C.

Kryger [21]2 years ago
4 0

Answer: I have no idea either i need help aswell

Explanation:

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Convection occurs when thermal energy is transferred by the movement of
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Convection is the transfer of thermal energy from one place to another by the movement of gas or liquid particles. How does this happen? As a gas or liquid is heated, the substance expands. This is because the particles in liquids and gases gain kinetic energy when they are heated and start to move faster.

6 0
2 years ago
Water flows into a horizontal, cylindrical pipe at 1.4 m/s. the pipe then narrows until its diameter is halved. what is the pres
inna [77]

According to the Bernoulli's equation,the pressure difference between the wide and narrow ends of the pipe is given by

\Delta P= \frac{1}{2} \rho ( v^2_{2} - v^2_{1} )

Here,  v_{1} is the velocity of water through wide ends of cylindrical pipe and v_{2} is the velocity of water through narrow ends of cylindrical pipe.

Given, v_{1} =1.4 m/s

Now from equation continuity,

v_{1} A_{1} = v_{2} A_{2}.

Here, A_{1} and A_{2} are cross- sectional areas of wide and narrow ends of cylindrical pipe.

As pipe is circular, so

v_{1} \pi r^2_{1} = v_{2} \pi r^2_{2}.

At the second point, the diameter is halved, which means the radius is also halved. Therefore,

v_{1} r^2_{1} = v_{2}(\frac{1}{2} r_{1})^2 \\\\ v_{2} = 4 v_{1}

v_{2} = 4 \times 1.4 = 5.6 m/s

Substituting these values  with the density of water is 1000 \ kg/m^3 in pressure difference formula we get.

\Delta P= \frac{1}{2} \rho ( v^2_{2} - v^2_{1} )=\frac{1}{2}\times 1000 kg/m^3(5.6^2-1.4^2)\\\\ \Delta P = 14700\ Pa

3 0
3 years ago
Read 2 more answers
A 4 kW vacuum cleaner is powered by an electric motor whose efficiency is 90%. (Note that the electric motor delivers 4 W of net
RoseWind [281]

Answer:3.6\ kW

Explanation:

Given

Power Supplied [tex]P_{input}=4\ kW[/tex]

Efficiency of the motor \neta =90\%

and \neta =\dfrac{\text{Power output}}{\text{Power input}}

\Rightarrow 0.9=\dfrac{P_{out}}{4}

\Rightarrow P=0.9\times 4

\Rightarrow P=3.6\ kW

So, vacuum cleaner delivers a power of 3.6\ kW

3 0
2 years ago
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