Answer:
first 2 yes 3rd one no 4th one yes last one no
Explanation:
Answer:
The time that the drop is falling =35.875 s
Explanation:
Using one of newton's equation of motion
g = V-u/t ................ Equation 1
Where V = final velocity, u = initial velocity, g = acceleration due to gravity of the moon, t = time.
<em>Note:</em> for a dropping object, u = 0 m/s
g = V/t.................... Equation 2
making t the subject of equation 2 above
t = V/g................. Equation 3
<em>Given: V= 57.4 m/s, g = 1.6 m/s²</em>
Substituting these values into equation 3
t = 57.4/1.6
t = 35.875 s
t = 35.875 s
The time that the drop is falling = 35.875 s
Answer:
B.useful products
Explanation:
industry is a sector that produces goods or services within an economy
Answer:
Explanation:
Using the lens formula
1//f = 1/u+1/v
f is the focal length of the lens
u is the object distance
v is the image distance
For convex lens
The focal length of a convex lens is positive and the image distance can either be negative or positive.
Given f = 20cm and u = 10cm
1/v = 1/f - 1/u
1/v = 1/20-1/10
1/v = (1-2)/20
1/V = -1/20
v = -20/1
v = -20 cm
Since the image distance is negative, this shows that the nature of the image formed by the convex lens is a <u>virtual image</u>
<u></u>
For concave lens
The focal length of a concave lens is negative and the image distance is negative.
Given f = -20cm and u = 10cm
1/v = 1/f - 1/u
1/v = -1/20-1/10
1/v = (-1-2)/20
1/V = -3/20
v = -20/3
v = -6.67 cm
Since the image distance is negative, this shows that the nature of the image formed by the concave lens is a <u>virtual image</u>
<u></u>
Answer:
Minimum capacitance = 200 μF
Explanation:
From image B attached, we can calculate the current flowing through the capacitors.
Thus;
Since V=IR; I = V/R = 5/500 = 0.01 A
Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V
So minimum capacitance will be determined from;
i(t) = C(dv/dt)
So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]
C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF