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3 years ago

Please help for 30 points write at least 3 rules that summarize how magnets move objects.

Physics

2 answers:

guajiro [1.7K]3 years ago

5 0

1-long, straight wires, 2-free moving charges in magnetic fields, and 3-the solenoid rule (which are loops of current)

IrinaK [193]3 years ago

3 0

Answer:

Magnets work by using Earth's magnetic pull.

Explanation:

Magnets move objects because they are made of steel or metal. And for that reason, they can stick to objects that are metal.

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Study the four transverse waves shown. Compare the properties of waves B, C, & D to that of wave A.

erica [24]

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4 years ago

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3 years ago

In the picture of a planet in orbit around its star area a is double that of area b. What is true of the time the planet takes t

aalyn [17]

The Kepler's laws predict the planetary motion, so there are three laws for this, namely:

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3. The square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit.

So, let's use second law. The Sun sweeps out equal areas during equal intervals of time means that if A = B, the time the planet takes to travel A1A2 is equal to the time the planet takes to travel B1B2, but given that A = 2B, then takes twice the time to travel A1A2 compared to B1B2.

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4 years ago

Assume that the electric field E is equal to zero at a given point. Does it mean that the electric potential V must also be equa

lyudmila [28]

Answer:

No, this doesn't mean the electric potential equals zero.

Explanation:

In electrostatics, the electric field $\vec{E}$ is related to the gradient of the electric potential V with :

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r})$

This means that for constant electric potential the electric field must be zero:

$V(\vec{r}) = k$

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r}) = - \vec{\nabla} k$

$\vec{E} (\vec{r}) = - (\frac{\partial}{\partial x} , \frac{\partial}{\partial y } , \frac{\partial}{\partial z}) k$

$\vec{E} (\vec{r}) = - (\frac{\partial k}{\partial x} , \frac{\partial k}{\partial y } , \frac{\partial k}{\partial z})$

$\vec{E} (\vec{r}) = - (0,0,0)$

This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

$V(\vec{r})= (x+2)^2 (y+4)^3 (z+5)^4$

give an electric field of zero at point (0,0,0)

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4 years ago