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4 years ago

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A loop is oriented perpendicular (0 deg) to a 0.0817 T magnetic field. The magnetic flux through the loop is 5.90 x 10^-6 Wb. Wh

at is the area of Skip the loop?

1 answer:

blondinia [14]4 years ago

8 0

Answer:

area is 7.22×10^-5 m^2

Explanation:

let B be the magnetic field strength, A be the area of the skip the pool.

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A 250 g air-track glider is attached to a spring with springconstant 4.0 N/m. Th damping constant due to air resistance is0.015

vaieri [72.5K]

Answer:

33.33 seconds

Explanation:

$N=\dfrac{1}{e}N_0$

$N_0$ = Initial length pulled = 20 cm

b = Damping constant = 0.015 kg/s

k = Spring constant = 4 N/m

m = Mass of glider = 250 g

Time period is given by

$T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{0.25}{4}}\\\Rightarrow T=1.57079632679\ s$

Using exponential decay formula

$N=N_0e^{\dfrac{-bt}{m}}$

Final amplitude = Initial times decay

$\dfrac{1}{e}0.2=0.2e^{\dfrac{-0.015t}{2\times 0.25}}\\\Rightarrow 0.2=0.2e^{\frac{-0.015t}{2\cdot \:0.25}+1}\\\Rightarrow e^{\frac{-0.015t}{2\cdot \:0.25}+1}=1\\\Rightarrow \ln \left(e^{\frac{-0.015t}{2\cdot \:0.25}+1}\right)=\ln \left(1\right)\\\Rightarrow \left(\frac{-0.015t}{2\cdot \:0.25}+1\right)\ln \left(e\right)=\ln \left(1\right)\\\Rightarrow \frac{-0.015t}{2\cdot \:0.25}+1=\ln \left(1\right)\\\Rightarrow -\frac{0.015t}{0.5}=-1\\\Rightarrow -0.000225t=-0.0075\\\Rightarrow t=33.33\ s$

The time taken is 33.33 seconds

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4 years ago

A series RLC circuit has a resistance of 28 Ω and an impedance of 105 Ω. If the rms voltage applied to the circuit is 140 V, wha

sergiy2304 [10]

Answer:49.8W

Explanation:

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3 years ago

Are stars really planets?

Tems11 [23]

Stars are not really planets because they are far, far away from our solar system.
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3 years ago

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an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the

Gnom [1K]

The current drawn by the electric frying pan is <u>27.295 A.</u>

<u />

Power of toaster, P1 = 1800 W

Power of electric frying pan, P2 = 1400 W

Power of lamp, P3 = 75 W

Three devices are in parallel combination. So their Voltage difference is the same.

∆V = 120 Volt

Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A

Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A

Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A

Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A

Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.

The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.

Learn more about current here:-brainly.com/question/24858512

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2 years ago

A motorcycle of mass 250 kg drives around a circle with a centripetal acceleration of 3.4 m/s2. What is the centripetal force ac

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Hope this helps and have a nice day!

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3 years ago

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