<u>Answer:</u> The mass of sodium acetate that must be added is 30.23 grams
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
Molarity of acetic acid solution = 0.200 M
Volume of solution = 1 L
Putting values in above equation, we get:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
We are given:
= negative logarithm of acid dissociation constant of acetic acid = 4.74
pH = 5.00
Putting values in above equation, we get:
To calculate the mass of sodium acetate for given number of moles, we use the equation:
Molar mass of sodium acetate = 83.06 g/mol
Moles of sodium acetate = 0.364 moles
Putting values in above equation, we get:
Hence, the mass of sodium acetate that must be added is 30.23 grams