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Marina CMI [18]
3 years ago
9

David kept 100 grams of radioactive sodium in a container. He observed the amount of sodium left in the container after regular

intervals of time and recorded them in the table shown below.
Time (hours) Amount of sodium in container (in grams)
0 100
15 50
30 25
45 12.5

Based on the observations, which of these is most likely David's inference?
A.The half life period of radioactive sodium is 15 hours.
B.The half life period of radioactive sodium is 50 hours.
C.The amount of sodium left in the container after 60 hours will be 10.5 grams.
D.The amount of sodium left in the container after 60 hours will be 1.5 grams.
Chemistry
2 answers:
Anna [14]3 years ago
5 0
First we have to understand what a half life is. A half life is a measure of time when the amount of a certain object is 50% of the original amount. Hence the answer for this is letter A. The initial amount is 100. fifty percent of 100 is 50 and that happens after 15 hours. Hence, 15 hours is the half life period. 
Fudgin [204]3 years ago
5 0

Answer: A. The half life period of radioactive sodium is 15 hours.

Explanation:

Half life is the time taken by a reactant to reduce to its original concentration. It is designated by the symbol t_\frac{1}{2}.

Given:

At 0 hours the amount of sodium in container is 100 grams

After 15 hours , the amount of sodium in container is 50 grams which is half of the original amount of 100 grams.

It will take 15 hours for half of a 100 g sample to decay to half of the amount i.e. 50 grams.

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The air pressure inside a submarine is 1.24 atm. What would be the height of a column of mercury (mm Hg) balanced by this pressu
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Which of the following will have the highest melting point C6H12O6<br>KOI <br>NH3 <br>I2
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3 0
3 years ago
8. Calculate (H^+), (OH^-), pOH and the pH for a 0.00024 M solution of calcium hydroxide. Must show work!
Margaret [11]

Answer:

1. [H⁺] = 2.0×10¯¹¹ M

2. [OH¯] = 4.8×10¯⁴ M

3. pOH = 3.3

4. pH = 10.7

Explanation:

From the question given above, the following data were obtained obtained:

Molarity of Ca(OH)₂ = 0.00024 M

We'll begin by calculating the concentration of the hydroxide ion [OH¯]. This can be obtained as follow:

Ca(OH)₂ (aq) —> Ca²⁺ + 2OH¯

From the balanced equation above,

1 mole of Ca(OH)₂ produced 2 moles of OH¯.

Therefore, 0.00024 M Ca(OH)₂ will produce = 2 × 0.00024 = 4.8×10¯⁴ M OH¯

Thus, the concentration of the hydroxide ion [OH¯] is 4.8×10¯⁴ M

Next, we shall determine the pOH of the solution. This can be obtained as follow:

Concentration of the hydroxide ion [OH¯] = 4.8×10¯⁴ M

pOH =?

pOH = –Log [OH¯]

pOH = –Log 4.8×10¯⁴

pOH = 3.3

Next, we shall determine the pH of the solution. This can be obtained as follow:

pOH = 3.3

pH =?

pH + pOH = 14

pH + 3.3 = 14

Collect like terms

pH = 14 – 3.3

pH = 10.7

Finally, we shall determine the concentration of hydrogen ion [H⁺]. This can be obtained as follow:

pH = 10.7

Concentration of hydrogen ion [H⁺] =?

pH = –Log [H⁺]

10.7 = –Log [H⁺]

Divide both side by –1

–10.7 = Log [H⁺]

Take the antilog of –10.7

[H⁺] = Antilog (–10.7)

[H⁺] = 2.0×10¯¹¹ M

SUMMARY:

1. [H⁺] = 2.0×10¯¹¹ M

2. [OH¯] = 4.8×10¯⁴ M

3. pOH = 3.3

4. pH = 10.7

5 0
3 years ago
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Roman55 [17]
0.5 mole of Mg=12 grams= 0.5x atoms
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