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Mekhanik [1.2K]
2 years ago
5

can someone do my iready please its due in 4 hours 3 ill give 20 points for it!!!!!! PLEASEEEE (*´◒`*)

Mathematics
1 answer:
Dima020 [189]2 years ago
6 0

Answer:

YAYA

Step-by-step explanation:

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I need to know the equation for this table!
Kobotan [32]

The equation for the table is y=2x+3.

7 0
3 years ago
a graphic designer wants to know the number of regions that are formed when circles overlap in particular. can she find a rule t
kumpel [21]

Answer:

A. 2

Step-by-step explanation:

Its successive multiples and it increases:

+2, +4, +6, +8

it increases by 2 every time which is successive multiples so the answer is A, 2.

3 0
3 years ago
Find the volume of the cylinder.
Georgia [21]
<h3>Answer:</h3><h3>Exact volume = 32pi</h3><h3>Approximate volume =  100.48</h3>

The approximate volume only applies when pi = 3.14

Use either answer, but not both of course.

===============================================

Work Shown:

V = volume of cylinder

V = pi*r^2*h

V = pi*2^2*8

V = pi*32

V = 32pi .... exact volume in terms of pi

V = 32*3.14

V = 100.48 .... approximate volume when we use pi = 3.14

6 0
2 years ago
What is the expression for the difference of 4 and the quotient of w and 3 is equal to 29
JulsSmile [24]

The answer is

w ÷ 3 - 4 = 29

8 0
3 years ago
Find the obtuse angle between the following pair of straight lines.
ioda

Given:

y=-2

y=\sqrt{3}x-1

To find:

The obtuse angle between the given pair of straight lines.

Solution:

The slope intercept form of a line is

y=mx+b     ...(i)

where, m is slope and b is y-intercept.

The given equations are

y=0x-2

y=\sqrt{3}x-1

On comparing these equations with (i), we get

m_1=0

m_2=\sqrt{3}

Angle between two lines whose slopes are m_1\text{ and }m_2 is

\tan \theta=\left|\dfrac{m_2-m_1}{1+m_1m_2}\right|

Putting m_1=0 and m_2=\sqrt{3}, we get

\tan \theta=\left|\dfrac{\sqrt{3}-0}{1+(0)(\sqrt{3})}\right|

\tan \theta=\left|\dfrac{\sqrt{3}}{1+0}\right|

\tan \theta=\pm \sqrt{3}

Now,

\tan \theta= \sqrt{3} and \tan \theta=-\sqrt{3}

\tan \theta= \tan 60^\circ and \tan \theta=\tan (180^\circ-60^\circ)

\theta= 60^\circ and \theta=120^\circ

120>90, so it is an obtuse angle and 60, so it is an acute angle.

Therefore, the obtuse angle between the given pair of straight lines is 120°.

6 0
2 years ago
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