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Nadya [2.5K]
3 years ago
10

When graphing inequalities, where can the solutions be found?

Mathematics
1 answer:
Firdavs [7]3 years ago
4 0
The answer is c cuz the shaded overlapping section represents the answer
You might be interested in
Which statement illustrates the associative property of addition?
Alex73 [517]
I think it’s B because
3 0
2 years ago
What is the solution to the system of equations?<br> x = -4y<br> 3x + 2y = 20
sergeinik [125]

Answer:

(x, y) = (8, -2)

Step-by-step explanation:

Substitute:

3(-4y) + 2y = 20

-12y + 2y = 20

-10y = 20

y = -2

x = -4(-2) = 8

3 0
2 years ago
Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of vector QP .
Katyanochek1 [597]

Answer:

a)The component form is

\vec {QP}=\binom{ - 1}{ - 8}

b)The magnitude is √65

c) <2,14>

Step-by-step explanation:

Recall that:

\vec {QP}=\vec {OP}-\vec{OQ}

We substitute the position vectors to get:

\vec {QP}=\binom{ - 8}{7} -  \binom { - 7}{15}

We subtract the corresponding components to obtain:

\vec {QP}=\binom{ - 8 -  - 7}{7 - 15}

This gives:

\vec {QP}=\binom{ - 8  + 7}{7 - 15}

This simplifies to:

\vec {QP}=\binom{ - 1}{ - 8}

The magnitude of a vector in the component form:

\binom{x}{y}

is

\sqrt{ {x}^{2}  +  {y}^{2} }

This means:

|\vec {QP}|= \sqrt{ {( - 1)}^{2}  +  {( - 8)}^{2} }

This simplifies to:

|\vec {QP}| = \sqrt{ 1 +  64 }

|\vec {QP}| = \sqrt{ 65 }

c) We have the vectors u = <4, 8>, v = <-2, 6>.

We want to find:

u+v

This implies that:

u+v=<4,8>+<-2,6>

We add the corresponding components to get;

u+v=<4+-2,8+6>

This simplifies to:

u+v=<2,14>

7 0
3 years ago
Can you help me with number 2 please show me how you did it thank you
denpristay [2]
Distraibutiv peorpoty
a(b+c)=ab+ac

we have
3a+7+2(3+a)
distribute first
2(3+a)=6+2a

now we have
3a+7+6+2a
move like terms together
3a+2a+7+6
add lke terms
5a+13
7 0
2 years ago
27 - [ 38 - { 46 - ( 15 - 25) }]​
oee [108]

Answer:

45

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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