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Nadya [2.5K]
3 years ago
10

When graphing inequalities, where can the solutions be found?

Mathematics
1 answer:
Firdavs [7]3 years ago
4 0
The answer is c cuz the shaded overlapping section represents the answer
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Can someone please answer. There is one problem. There's a picture. Thank you.
svetoff [14.1K]
You have to find the area of each face and add them all together. You also need to find the unknown side which is indicated in the picture i attached.
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CAN SOMEBODY HELP. Unscramble the words to correctly to state a fact.
qaws [65]

Answer:

Cells create usable energy through Cellular Respiration.

Step-by-step explanation:

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3 years ago
2/3÷-4/5 what is two thirds divided by negative four fifths
RUDIKE [14]
I think that this is the resolution
2/3×5/-4 = 10/-12
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6 0
3 years ago
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What is the factored form of 2x2 + x-3?
Vesnalui [34]

Answer:

Step-by-step explanation:

a = 2, b = 1, c = -3

We need to factor this by finding the product of a and c, then from there find which factors of a * c will either add or subtract to give us b.

a * c = 6  and the factors of 6 and 1 and 6, 2 and 3.  Well, 6 - 1 doesn't equal 1 and neither does 6 + 1.  So our factors are 3 and 2.  In order to combine those to get a 1 (our b), we will subtract 2 from 3 since 3 - 2 = 1.  That means that 3 is positive and 2 is negative.  Filling in the formula with 3 and 2 in place of 1 looks like this (always remember to put the absolute value of the largest number first):

2x^2+3x-2x-3=0

Group the first 2 terms together and the second 2 term together in order to factor:

(2x^2+3x)-(2x-3)=0 and factor out what's common in each set of parenthesis.

x(2x+3)-1(2x+3)=0

Notice that when we factor out a -1 from the second set of parenthesis, we can distribute it back in to get the equation we started with.  We know that factoring by grouping "works" if what is inside both sets of parenthesis is exactly the same.  Ours are identical: (2x + 3).  That is common now, and can be factored out:

(2x+3)(x-1)=0

That matches your first choice

6 0
3 years ago
Tanya drove 312 hours and used 13 tank of gas. For how long could Tanya drive using​ 12 ​tank of gas? In simplest form.
madreJ [45]
312/13=24
24*12= 288 hours
5 0
3 years ago
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