All categories

2 years ago

Simple word problem, I’ll mark brainliest try to explain ur answer to please!

Mathematics

2 answers:

IceJOKER [234]2 years ago

5 0

Answer:

26.8

Step-by-step explanation:

x/145 = 18.5/100

cross-multiply:

100x = 2682.5

x = 26.8

Jlenok [28]2 years ago

4 0

Answer:

26.825

Step-by-step explanation:

when you find 18.5 percent of 145 pounds you will get your answer. hope this helps

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The puppy daycare has 38 doggie treats for 9 dogs to share evenly. The leftovers will be placed back into the jar.

Svetlanka [38]

The answer is A. 2

9x4=36
38-36=2

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3 years ago

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0.3 in the form a and b

konstantin123 [22]

The only way I am can you I love my you can be do not know want r a to a party in for you every night before a federal court and then it will

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3 years ago

What is the area of the figure

Tomtit [17]

A²+b²=c²
a=b because it has 2 45° angles and one 90 so it is isosceles right triangle

∴ a² + a² = c²
2a²=24²
2a²=576
a²=288
a=√288
a=16.97056275

Therefore. With A=1/2bh
A=(1/2) * 16.97056275 * 16.97056275
= (1/2) * 288
= 144

144 ft²

4 0

3 years ago

Equation for "five elevenths times a number is 55"

nika2105 [10]

Let the unknown number be x.

5/11 * x = 55

Since x is being multiplied by 5/11, and you want x alone, you need to multiply both sides of the equation by the reciprocal of 5/11 which 11/5.

11/5 * 5/11 * x = 55/1 * 11/5

x = 605/5

x = 121

Answer: The number is 121.

4 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago