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3 years ago

If the period of a given wave is 6 seconds, what is the frequency of the wave?

Physics

1 answer:

Ann [662]3 years ago

6 0

Answer:

$\text{B. }0.17\:\mathrm{Hz}$

Explanation:

The frequency of a wave is given by $f=\frac{1}{t}$ , where $t$ is the period of the wave.

Substituting $t=6$ , we get:

$f=\frac{1}{6}\approx \boxed{\text{B. }0.17\:\mathrm{Hz}}$

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A 125kg bumper car going 12m/s hits a 235kg bumper car going -13m/s.if the first car bounces back at -12.5m/s what is the veloci

vovikov84 [41]

According to the law of conservation of momentum:

$m_{1}v_{1}+m_{2}v_{2}=m_{1}v_{1}'+m_{2}v_{2}'$

m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision

Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.

m1 = 125 kg v1 = 12m/s v'1 = -12.5m/s
m2 = 235kg v2 = -13m/s v'2 = ?

$m_{1}v_{1}+m_{2}v_{2}=m_{1}v_{1}'+m_{2}v_{2}'$
$(125kg)(12m/s)+(235kg)(-13m/s)=(125kg)(-12.5m/s)+(235kg)(v_{2}'$
$1,500kg.m/s+(-3055kg.m/s)=(-1562.5kg.m/s)+(235kg)(v_{2}')$
$-1,555kg.m/s=(-1562.5kg.m/s)+(235kg)(v_{2}')$

Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.

$-1,555kg.m/s + 1562.5kg.m/s=(235kg)(v_{2}')$
$7.5kg.m/s=(235kg)(v_{2}')$
$(7.5kg.m/s)/(235kg)=(v_{2}')$
$0.03m/s=(v_{2}')$

The velocity of the 2nd car after the collision is 0.03m/s.

5 0

3 years ago

- In Einstein's famous equation E = me?, describing the

mel-nik [20]

Answer:

option C is correct

Explanation:

8 0

3 years ago

A bullet is fired horizontally from a 17.7 m high cliff at a speed of 482.0. What is the distance from the cliff that the bullet

Marysya12 [62]

Answer:

Horizontal distance=?m

Explanation:

Horizontal velocity,u=482ms⁻¹

Height of the cliff=17.7m

Horizontal distance,R=?

R=v×√2h/g

5 0

3 years ago

If you are describing the displacement of an object with respect to a reference point, you should use

Leya [2.2K]

You should use B. a vector

6 0

3 years ago

Air conditioners sold in the United States are given a seasonal energy-efficiency ratio (SEER) rating that consumers can use to

amid [387]

Answer:

112.58

Explanation:

The Coefficient of Performance of any system is denoted by COP=Q/W, where Q is the useful heat supplied or removed and W is the work required by the system. According to the first law of thermoddynamics Qh= Qc + W, where Qh is the heat transfered to the hot reservoir and Qc is the heat collected from the cold reservoir. Substituting the values for W and apllying the limitation for maximum theoretical efficiency we end up with the eqution shown below.

The Coefficient of Performance of air conditioner or COP is denoted by

COP(cool) = Tc/(Th- Tc)

where Tc: the lowest temperature

Th: the highest temperature

converting the values to Kelvin and adding them in the above equation

COP(cool) = (25+273)/((34+273)-(25+273))

= 298/(307-298)

= 298/9 = 33.11

From the question, it is stated that COP=SEER/3.4

hence, SEER= COP * 3.4

SEER= 33.11 * 3.4 = 112.58

7 0

4 years ago