Answer:
(a) = 0 N
(b) = 2.4 N
Explanation:
given
box of banana weight = 40.0 N
coefficient of static friction μ = 0.40
coefficient of kinetic friction = 0.20
a). when no horizontal force is applied .
according to Newton 's third law of motion If there is no force applied to the box,so the frictional force exerted is 0 N
b) magnitude of friction force
box and the box is initially at rest
friction force =.Static friction coefficient × weight of the box
friction force = 0.40 × 6
friction force = 2.4 N
To solve this problem it is necessary to apply the concepts given by Malus regarding the Intensity of light.
From the law of Malus intensity can be defined as
Where
Angle From vertical of the axis of the polarizing filter
Intensity of the unpolarized light
The expression for the intensity of the light after passing through the first filter is given by
Replacing we have that
Re-arrange the equation,
Re-arrange to find \theta
The value of the angle from vertical of the axis of the second polarizing filter is equal to 30.2°
A guessing answer the best answer but you have had to subtract the answer by the equation that it was giving u
Answer:
3.75 m/s
Explanation:
From the question given above, the following data were obtained:
Acceleration (a) = 1.5 m/s²
Initial velocity (u) = 0 m/s
Time (t) = 2.5 s
Final velocity (v) =?
a = (v – u) / t
1.5 = (v – 0) / 2.5
1.5 = v / 2.5
Cross multiply
v = 1.5 × 2.5
v = 3.75 m/s
Hence, the escape velocity of the squirrel is 3.75 m/s
Answer:
in which standard you are, i am typing your answer till please reply.
