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AfilCa [17]
3 years ago
14

One student completed a cookie mining experiment in a very short period of time. In your own words, explain how 'time is money'

in the cookie mining experiment and apply it to the real world.
Physics
1 answer:
Lera25 [3.4K]3 years ago
6 0
During the cookie mining experiment, the student had to choose the tools to perform the experiment. These tools of course cost money.
Now, if the way the student conducts his/her experiment is not optimized, the student would have to spend more money and time to get the experiment done.

This also applies to real life where you have to optimize the procedures of getting any task or project completed. Otherwise, you will find yourself paying more money and consuming more time to get the output.

Another perspective of seeing how "time is money" is when a certain company/factory abides by a contract to deliver certain goods in specific time. If the company/factory fails to deliver the goods, it will pay a penalty for this delay. 

Based on the above, time is money in most aspects of life. Therefore, you must always try to optimize your work.
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Zarrin [17]
Follow stop drop and roll if the fire is in the room
Other wise exit immediately and find the nearest fire point. Then when you are out phone the fire services.
I hope this helps :)
5 0
3 years ago
Read 2 more answers
A planet of mass 7.00 1025 kg is in a circular orbit of radius 6.00 1011 m around a star. The star exerts a force on the planet
BARSIC [14]

Answer:

A) 1.88 * 10^17 m

B) 1.22 * 10^34 J

C) 1.95 * 10^34 J

Explanation:

Parameters given:

Mass of planet = 7.00 * 10^25 kg

Radius of orbit = 6.00 * 10^11 m

Force exerted on planet = 6.51 * 10^22 N

Velocity of planet = 2.36 * 10^4 m/s

A) The distance traveled by the planet is half of the circumference of the orbit (which is circular).

The circumference of the orbit is

C = 2 * pi * R

R = radius of orbit

C = 2 * 3.142 * 6.0 * 10¹¹

C = 3.77 * 10¹² m

Hence, distance traveled will be:

D = 0.5 * 3.77 * 10¹²

D = 1.88 * 10 ¹² m/s

B) Work done is given as:

W = F * D

W = 652 * 10²² * 1.88 * 10¹¹

W = 1.22 * 10³⁴ J

C) Change in Kinetic energy is given as:

K. E. = 0.5 * m * v²

K. E. = 0.5 * 7 * 10^25 * (2.36 * 10^4)²

K. E. = 1.95 * 10³⁴ J

7 0
3 years ago
A proton enters a uniform magnetic field of strength 1 T at 300 m/s. The magnetic field is oriented perpendicular to the proton’
scZoUnD [109]

A charged particle moving in a magnetic field experiences a force equal to:

\vec{F}=q\vec{v}\times \vec{B}

Thus, the magnitude of the force that the proton experiences is given by:

F=qvBsin\theta

The magnetic field is perpendicular to the proton's velocity, therefore, we have \theta=90^\circ. Replacing the given values, we obtain:

F=1.6*10^{-19}C(300\frac{m}{s})(1T)sin(90^\circ)\\F=4.8*10^{-17}N

3 0
3 years ago
Which is correct about an ammeter?
s344n2d4d5 [400]

Answer:

b. The internal resistance must be much smaller than the other resistances in the circuit.

Explanation:

Ammeter is used to measure the current flowing through a circuit. It is connected in series configuration with the load. In such a scenario the resistance of the ammeter should be negligible so as to make sure that the voltage drop across the resistance of ammeter is zero and it shows the correct reading of the current in the circuit.

3 0
3 years ago
A current relationship is one that
Alex
C is the best answer
hope it helped
8 0
3 years ago
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