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3 years ago

Which term, taken from the celestial sphere, gives its name to a.m. and p.m.?

Physics

1 answer:

DaniilM [7]3 years ago

3 0

Options are. Zenith, Great circle, Equinox, or Meridan

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Juliana walks 45 meters East, 45 meters south and 45 meters north. What is her resultant displacement?

katrin2010 [14]

Her resultant displacement is (45 Meters East.)

She originally walks 45 meters east, then she goes south 45 meters, then north 45 meters. The south and north placements just make her go back to where her previous placements were before them. Making her 45 meters east.

6 0

3 years ago

George walks to a friend's house. He walks 750 meters North, then realizes he walked

Sauron [17]

Answer:

I think you are looking for the velocity, so the answer is 38.5 m/s

Explanation:

Velocity is giving by displacement/time. North will be positive and South will be negative, George travels 750 meters then travels -250 meters his displacement is then 750 - 250 or 500 meters. Divide that by 13 seconds to get 38.5 m/s.

4 0

3 years ago

At an accident scene on a level road, investigators measure a car's skid mark to be 88 m long. It was a rainy day and the coeffi

german

Answer:

The speed was 26.91m/s (96.9 km/h)

Explanation:

Here you have to consider that at the beginning you have an amount of kinetic energy (K) that is dissipated because of the work done by friction forces (T). Since the car is stopped after the accident, all the energy has been dissipated. Thus, $K=T$ .

The definition of the kinetic energy is $K=1/2*m*v^2$ .

The work done by the friction forces is: $T=f*(m*g)*d$ . Where f is the friction coefficient, g is the gravity acceleration, m is the mass of the car and d is the skid marks longitude. Therefore,

$1.2*m*v^2=f*(m*g)*d$

Since m is in both sides it can be cancelled so it is not necessary to considered.

Then, the speed is determined by the following equation:

$v=\sqrt{2*f*g*d} =\sqrt{2*0.42*9.8m/s^2*88 m}=26.91 m/s$

4 0

4 years ago

What are the two ways in which weathering can occur

Bond [772]

Two types of weather are mechanical and chemical

5 0

3 years ago

Suppose we have two planets with the same mass, but the radius of the second one is twice the size of the first one. How does th

bogdanovich [222]

The free-fall acceleration on the second planet is one-fourth the value of the first planet.

Calculation:

Consider the mass of planet A to be, M

the mass of planet B to be, Mₓ = M

the radius of planet A to be, R₁

the radius of planet B to be, R₂

The acceleration due to gravity on planet A's surface is given as:

g = GM/R₁² - (1)

Similarly, the acceleration due to gravity on planet B's surface is given as:

g' = GM/R₂² [where, R₂ = 2R₁]

= GM/4R₁² -(2)

From equation 1 & 2, we get:

g/g' = GM/R₁² ÷ GM/4R₁²

g/g' = 4/1

Thus we get,

g' = 1/4 g

Therefore, the free-fall acceleration on the second planet is one-fourth the value of the first planet.

Learn more about free-fall here:

brainly.com/question/13299152

#SPJ4

6 0

2 years ago