Question

The largest graduated cylinder in my lab holds 2 L and has an inner diamter (the part that holds the water) of 8 cm. When it is full of 2 L of water, what is the pressure at the bottom of the cylinder in Pa?

Answer 1

Answer:

3924 Pa

Explanation:

Volume of cylinder = 2 L = 0.002 m^3  (1000 L = 1 m^3)

diameter of the inner cylinder = 8 cm = 0.08 m  (100 cm = 1 m)

radius of the inner cylinder = diameter/2 = 0.08/2 = 0.04 m

area of the inner cylinder = $\pi r^{2}$

where $\pi$ = 3.142,

and r = radius = 0.04 m

area of inner cylinder = 3.142 x $0.04^{2}$ = 0.005 m^2

height h of the water in this cylinder = volume/area

h = 0.002/0.005 = 0.4 m

pressure at the bottom of the cylinder due to the height of water = pgh

where

p = density of water = 1000 kg/m^3

g = acceleration due to gravity = 9.81 m/s^2

h = height of water within this cylinder = 0.4 m

pressure = 1000 x 9.81 x 0.4 = 3924 Pa