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emmasim [6.3K]
4 years ago
8

Apr 22, 1:11:18 PM

Physics
2 answers:
Salsk061 [2.6K]4 years ago
7 0

Answer: It’s 12

Explanation:

CaHeK987 [17]4 years ago
5 0

Answer: 4 inches I believe.

Explanation:

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What is the condition for an object experiencing free fall?
S_A_V [24]

Answer:

The body acts under the influence of gravity.

Explanation:

An object experiencing free fall is acting under the influence of gravitational force and the acceleration due gravity is positive for any falling object. The body is able to fall freely due to the effect of gravity on it. This gravity effect causes the body to get attracted to the earth's gravitational surface due to gravitational pull exerted on the body.

3 0
4 years ago
A rigid, insulated tank whose volume is 10 L is initially evacuated. A pinhole leak develops and air from the surroundings at 1
balandron [24]

Answer:

The answer is "143.74^{\circ} \ C , 8.36\ g, and \ 2.77\ \frac{K}{J}"

Explanation:

For point a:

Energy balance equation:

\frac{dU}{dt}= Q-Wm_ih_i-m_eh_e\\\\

W=0\\\\Q=0\\\\m_e=0

From the above equation:

\frac{dU}{dt}=0-0+m_ih_i-0\\\\\Delta U=\int^{2}_{1}m_ih_idt\\\\

because the rate of air entering the tank that is h_i constant.

\Delta U = h_i \int^{2}_{1} m_i dt \\\\= h_i(m_2 -m_1)\\\\m_2u_2-m_1u_2=h_i(M_2-m_1)\\\\

Since the tank was initially empty and the inlet is constant hence, m_2u-0=h_1(m_2-0)\\\\m_2u_2=h_1m_2\\\\u_2=h_1\\\\

Interpolate the enthalpy between T = 300 \ K \ and\ T=295\ K. The surrounding air  

temperature:

T_1= 25^{\circ}\ C\ (298.15 \ K)\\\\\frac{h_{300 \ K}-h_{295\ K}}{300-295}= \frac{h_{300 \ K}-h_{1}}{300-295.15}

Substituting the value from ideal gas:

\frac{300.19-295.17}{300-295}=\frac{300.19-h_{i}}{300-298.15}\\\\h_i= 298.332 \ \frac{kJ}{kg}\\\\Now,\\\\h_i=u_2\\\\u_2=h_i=298.33\ \frac{kJ}{kg}

Follow the ideal gas table.

The u_2= 298.33\ \frac{kJ}{kg} and between temperature T =410 \ K \ and\  T=240\ K.

Interpolate

\frac{420-410}{u_{240\ k} -u_{410\ k}}=\frac{420-T_2}{u_{420 k}-u_2}

Substitute values from the table.

 \frac{420-410}{300.69-293.43}=\frac{420-T_2}{{u_{420 k}-u_2}}\\\\T_2=416.74\ K\\\\=143.74^{\circ} \ C\\\\

For point b:

Consider the ideal gas equation.  therefore, p is pressure, V is the volume, m is mass of gas. \bar{R} \ is\  \frac{R}{M} (M is the molar mass of the  gas that is 28.97 \ \frac{kg}{mol} and R is gas constant), and T is the temperature.

n=\frac{pV}{TR}\\\\

=\frac{(1.01 \times 10^5 \ Pa) \times (10\ L) (\frac{10^{-3} \ m^3}{1\ L})}{(416.74 K) (\frac{8.314 \frac{J}{mol.k} }{2897\ \frac{kg}{mol})}}\\\\=8.36\ g\\\\

For point c:

 Entropy is given by the following formula:

\Delta S = mC_v \In \frac{T_2}{T_1}\\\\=0.00836 \ kg \times 1.005 \times 10^{3} \In (\frac{416.74\ K}{298.15\ K})\\\\=2.77 \ \frac{J}{K}

5 0
3 years ago
describe why people are better off not consuming an additional good or service if the marginal cost is greater than the marginal
yulyashka [42]
I hosestly don’t know sorry need the points
3 0
3 years ago
A passenger jet travels from Los angles to Bombay, India, in 22 h. The return flight takes 17 h. The difference in flight times
Hoochie [10]

Answer:

70.5 mph

Explanation:

A passenger jet travels from Los Angeles to Bombay, India, in 22h.

The return flight takes 17 h.

The difference in flight times is caused by winds over the Pacific Ocean that

blow primarily from west to east.

If the jet's average speed in still air is 550 mi/h what is the average speed

of the wind during the round trip flight? Round to the nearest mile per hour.

Is your answer reasonable?

:

Let w = speed of the wind

:

Write a distance equation (dist is the same both ways

17(550+w) = 22(550-w)

9350 + 17w = 12100 - 22w

17w + 22w = 12100 - 9350

39w = 2750

W = 2750/39

w = 70.5 mph seems very reasonable

:

Confirming if the solution by finding the distances using these value

17(550+70.5) = 10549 mi

22(550-70.5) = 10549 mi; confirms our solution of w = 70.5 mph

6 0
3 years ago
During a physical science lab investigating chemical reactions, several students placed a 30g antacid tablet in a 30g zip-lock b
ICE Princess25 [194]
30 Grams would be your answer (I took the test and got it right)
8 0
3 years ago
Read 2 more answers
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