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Lubov Fominskaja [6]
3 years ago
5

Please help please...

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

Thank You for your efforts

the first one is only one solution but the second one is only one thx

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What is (1-i)^3 <br> Please explain how you got that
My name is Ann [436]

\bf (1-i)^3\implies ~\hfill \begin{array}{cccccccl} 1^3&+&3(1)^2(-i)^1&+&3(1)^1(i)^2&+&(-i)^3\\\\ 1&+&(-3i)&+&(3i^2)&+&(-i^3)\\\\ 1&-&3i&+&3i^2&-&i^3 \end{array} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{let's recall that}}{i^2=-1\qquad \qquad i^3=-i} \\\\[-0.35em] ~\dotfill\\\\ 1-3i+3(-1)-(-i)\implies 1-3i-3+i\implies -2-2i

6 0
3 years ago
25 students are learning how to make balloon animals. There are 194 balloons to be shared equally among the students. How many b
alexdok [17]
25 students
194 balloons

194/25 = 7.76
Each student gets 7 balloons, 7 x 25 = 175 balloons will be used
194 - 175 = 19 balloons remaining (Answer to part 1 of this question)

If each student needs 8 balloons
8 * 25 = 200
200 - 194 = 6 ballons needed (Answer to part 2 of this question)

We also could have found the answer to part 2 by saying that we had 19 balloons left over when the students each were given 7 balloons
Each student needs another 1 balloon = 25 balloons, 
We have 19 left over
25 - 19 = 6 balloons need to be purchased (we got the same answer both ways so it is very likely we have the correct answer)
6 0
4 years ago
To play at bingo night there’s a $10 cover charge +2 dollar per bingo card. Write an equation for the cost (y) based on the numb
jasenka [17]

Answer:

y  = 2x+10

Step-by-step explanation:

y is the cost (which we don't know)

2x is the $2 per card with x representing the number of cards (which we don't know)

And of course 10 is the cover charge.

4 0
4 years ago
What is the recursive formula for this geometric sequence?<br> -2, -16, -128, -1024,
FinnZ [79.3K]
<h3>Answer: Choice A</h3>

The first line shown in choice A is a_1 = -2 which means "the first term is -2"

The next line in choice A means "the nth term (a_n) is found by multiplying the prior term (a_{n-1}) by 8". Put another way: multiply each term by 8 to get the next term.

first term = -2

second term = 8*(first term) = 8*(-2) = -16

third term = 8*(second term) = 8*(-16) = -128

fourth term = 8*(third term) = 8*(-128) = -1024

and so on.

3 0
4 years ago
Read 2 more answers
Write the product as a sum: 14cos(39x)sin(19x)
charle [14.2K]

Recall that

sin(<em>a</em> + <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) + cos(<em>a</em>) sin(<em>b</em>)

sin(<em>a</em> - <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) - cos(<em>a</em>) sin(<em>b</em>)

Adding these together gives

sin(<em>a</em> + <em>b</em>) + sin(<em>a</em> - <em>b</em>) = 2 sin(<em>a</em>) cos(<em>b</em>)

To get 14 cos(39<em>x</em>) sin(19<em>x</em>) on the right side, multiply both sides by 7 and replace <em>a</em> = 19<em>x</em> and <em>b</em> = 39<em>x</em> :

7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) + sin(-20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) - sin(20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

4 0
3 years ago
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