$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ y=\stackrel{\stackrel{a}{\downarrow }}{a}x^2\stackrel{\stackrel{b}{\downarrow }}{+b}x\stackrel{\stackrel{c}{\downarrow }}{+c} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\stackrel{\textit{no real roots}}{\textit{no solution}}\quad \checkmark \end{cases}$

6 0

2 years ago

Please help, I’ve been stuck on this question for about a hour now.

Hoochie [10]

6x + 5x + (x + 16) + (3x - 1) = 360
11x + x + 16 + 3x - 1
15x + 15 = 360
15x = 345
x = 23

6(23) = 138
((23) + 16) = 39
(3(23) - 1) =68
5(23) = 115

138 + 39 + 68 + 115 = 360

7 0

2 years ago

The midpoint of ST is M(7,3). One endpoint is T(7,5). Find the coordinates of the other endpoint S. Write the coordinates as dec

larisa [96]

Answer:

Step-by-step explanation:

ST = SM + TM

SM = X

TM = 5 - 3 = 2

SM = 2

4 0

2 years ago