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GarryVolchara [31]
3 years ago
11

Solve for X

Mathematics
1 answer:
DerKrebs [107]3 years ago
5 0

Answer:

One of the answers should be b or c

Step-by-step explanation:

SORRY IF I DID NOT DO IT RIGHT

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Jolie can read around 14 sentences per minute of her current novel. She wants to finish her reading before the movie comes out n
vladimir1956 [14]
This is what you would do
120 x 17= 2040
Or you could do 12 x 17 then, add a zero to the end of it.
Then you would divid from what you got when you did 120 x 17 by 60
That should give you the answer. 
Hope this helps if im not mistaken it should be 34 

2040 <span>60 </span>= 34

34 = 340 to the nearest tenth

34 = 34 to the nearest hundredth

34 = 34 to the nearest thousandth

= 0 to the nearest tenth

= 0 to the nearest hundredth

= 0 to the nearest thousandth



4 0
3 years ago
What is the maximum value of the function f(x) = -x2 + 4?
xenn [34]

Answer:

-x2+4=-x=4-2=2

-x=2

x= -2

8 0
3 years ago
What is the markdown from $90 to $75?
love history [14]

Answer:

$15.

Step-by-step explanation:

90-75=15, which is the difference between the two. Hope this helps.

5 0
3 years ago
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shutvik [7]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
B Which of the statements is true about the polygons below E D 120 degrees C 90 90 60 60 120 degrees 90 90 F D Polygon A Polygon
Serhud [2]

The statement that is true about the polygons is: the opposite angles of the rectangle are supplementary, therefore, a circle can be circumscribed about the rectangle.

<h3>What is a Circumscribed Quadrilateral?</h3>

An circumscribed quadrilateral is a quadrilateral whose four side lie tangent to the circumference of a circle. The opposite angles in an inscribed quadrilateral are supplementary, that is, when added together, their sum equals 180 degrees.

From the two figures given, the opposite angles of the rectangle are supplementary, therefore, a circle can be circumscribed about the rectangle. (Option D).

Learn more about circumscribed quadrilateral on:

brainly.com/question/26690979

#SPJ1

7 0
2 years ago
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