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Ira Lisetskai [31]
2 years ago
6

PLEASE PLEASE ANSERR THIS PLEASEEEE

Chemistry
1 answer:
Goryan [66]2 years ago
5 0

Answer:

I think it is c

Explanation:

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A typical refrigerator is kept at 4˚C, and a soda can has a pressure of
ss7ja [257]

Answer: The new pressure will be 1.42 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=1.18atm\\T_1=4^0C=(4+273)K=277K\\P_2=?\\T_2=60^0C=(60+273)K=333K

Putting values in above equation, we get:

\frac{1.18}{277}=\frac{P_2}{333}\\\\P_2=1.42

Hence, the new pressure will be 1.42 atm

7 0
2 years ago
How many moles are there in 8.50 X 1024 molecules of sodium sulfate, Na2SO3?
il63 [147K]

Answer:

<h2>14.12 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.50 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 14.119601...

We have the final answer as

<h3>14.12 moles</h3>

Hope this helps you

3 0
2 years ago
In a solution of pure water, the dissociation of water can be expressed by the following: H2O(l) + H2O(l) ⇌ H3O+(aq) + OH−(aq) T
kakasveta [241]

Answer:

  • [H₃O⁺] = 2.90 × 10⁻¹⁰ M

Explanation:

1)<u><em> Ionization equilibrium equation: given</em></u>

  • H₂O(l) + H₂O(l) ⇌ H₃O⁺(aq) + OH⁻(aq)

2) <em><u>Ionization equilibrium constant, at 25°C, Kw: given</u></em>

  • Kw = 1.0 × 10⁻¹⁴

<u>3) Stoichiometric mole ratio:</u>

As from the ionization equilibrium equation, as from the fact it is stated, the concentration of both ions, at 25°C, are equal:

  • [H₃O⁺(aq)] = [OH⁻(aq)] = 1.0 × 10⁻⁷ M

  • ⇒ Kw = [H3O⁺] [OH⁻] = 1.0 × 10⁻⁷  × 1.0 × 10⁻⁷  = 1.0 × 10⁻¹⁴ M

<u><em>4) A solution has a [OH⁻] = 3.4 × 10⁻⁵ M at 25 °C </em></u><em><u>and you need to calculate what the [H₃O⁺(aq)] is.</u></em>

Since the temperature is 25°, yet the value of Kw is the same, andy you can use these conditions:

  • Kw = 1.0 × 10⁻¹⁴ M², and

  • Kw = [H3O⁺] [OH⁻]

Then you can substitute the known values and solve for the unknown:

  • 1.0 × 10⁻¹⁴ M² = [H₃O⁺] × 3.4 × 10⁻⁵ M

  • ⇒ [H₃O⁺]  = 1.0 × 10⁻¹⁴ M² / ( 3.4 × 10⁻⁵ M ) = 2.9⁻¹⁰ M

As you see, the increase in the molar concentration of the ion [OH⁻] has caused the decrease in the molar concentration of the ion [H₃O⁺], to keep the equilibrium law valid.

6 0
3 years ago
Read 2 more answers
Which example is NOT a model?
lidiya [134]

Answer:

B

Explanation:

i think leter B it because

7 0
3 years ago
Read 2 more answers
What parts of a divers body are most affected by pressure changes?
Yanka [14]
I would say the head and heart because if you swim deep in the ocean you will feel pressure in your heart and head because the muscles in your body are closing in on them

hope i helped
5 0
3 years ago
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