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dem82 [27]
2 years ago
9

HELPPP PLEASE !/!/!/!/!/!/!/!

Chemistry
1 answer:
eduard2 years ago
6 0

Answer:

the second question should be along the staircase

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3. Crystalline structural unit of barium metal is a body-centered cubic cell. The edge length of the unit cell is 5.02x10-8 cm.
tiny-mole [99]

Answer:

The Avogadro's  number is N_A     =  6.02289 *10^{23}

Explanation:

From the question we are told that

   The edge length is  L   = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100}  =  5.02 * 10^{-10}

    The density of the metal is \rho =  5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3}  * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3

     The molar mass of  Ba is  Z  =  137.3 \ g/mol = \frac{137.3}{1000} =  0.1373 \  kg / mol

     

Generally the volume of a unit cell is  

       V =  L^3

substituting value

        V =  [5.02 *10^{-10}]^3

         V = 1.265*10^{-28}\ m^3  

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be  (BCC),

The volume of barium atom is  

        V_a  =  \frac{V}{2}  * 0.68

substituting value

        V_a  =  \frac{ 1.265*10^{-28}}{2}  * 0.68

        V_a  = 4.301 *10^{-29} \ m^3

The Molar mass of barium is mathematically represented as

      Z  =  N_A V_a *  \rho

Where N_A is the Avogadro's number

 So  

      N_A     =   \frac{ Z}{ V_a *  \rho}

substituting value

     N_A     =   \frac{ 0.1373}{ 4.301*10^{-29} *  5.3*10^{3}}

     N_A     =  6.02289 *10^{23}

4 0
2 years ago
HELP ASAP ITS TIMED!!!
Tpy6a [65]

Answer:

C would be the right answer

5 0
3 years ago
Read 2 more answers
What is the current produced when a 12-Volt battery encounters a resistance of 20 Ohms?
Verdich [7]

Answer:

Explanation:

V = IR

I = V/R

I = (12V)/(20Ω)

I = 0.6 A

4 0
2 years ago
Which best describes the motion of molecules in the gaseous state?
artcher [175]

Answer:

They spread apart to fill the enclosed object. In other words they move freely...

hope this helped you

please mark as the brainliest(ㆁωㆁ)

5 0
2 years ago
The combustion of hydrogen and oxygen is commonly used to
posledela

Answer:

6.66 mol

Explanation:

(atm x L) ÷  (0.0821 x K)

(0.875 x 250) ÷  (0.0821 x 400)

=6.66108

5 0
2 years ago
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