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Tasya [4]
3 years ago
8

I need help I am lost please help me

Mathematics
1 answer:
Evgen [1.6K]3 years ago
4 0

Answer:

6

Step-by-step explanation:

Because 6 is 6 times as 1, 12 is 6 times as 2, 18 is 6 times as 3 and so on.

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Solve If QR = 6x + 1, PR = 14x - 13, and PQ = 5x - 2, find PR
solong [7]

Answer:

P____Q____R

PR= PQ+ QR

(14x-13) = (5x-2)+(6x+1)

14x-13= 11x – 1

14x – 11x = 13–1

3x = 12

x= 12/ 3

x= 4

PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5

If you want (PQ , QR ) this is the solution

PQ =5x-2=5(4)-2=20-2=18

QR =6x+1=6(4)+1=24+1=25

I hope I helped you^_^

7 0
3 years ago
A salad dressing recipe calls for ¾ cup of oliva oil for every ½ cup of vinegar. How many cups of vinegar are needed for 2 cups
nika2105 [10]

Answer:

1\frac{1}{3}  

Step-by-step explanation:

Write a proportion comparing the Oliva Oil to Vinegar = Oliva Oil to Vinegar.

\frac{3/4}{1/2} = \frac{2}{?}

3/4 ? = 2(1/2)

3/4? = 1

  ? = 1 ÷ 3/4

  ? = 1 × 4/3

  ?  = 4/3

  ? = 1\frac{1}{3}

6 0
3 years ago
Determine whether the following sequence is geometric. If so, find the common ratio.
Doss [256]

Geometric sequence

-5 each term is multiplied by -5

7 0
3 years ago
Read 2 more answers
Help i need help please
Molodets [167]

The coefficient would be 18. The exponent for g would be 18. The exponent for h would be 9.

Add the exponents of the same variable and multiply the coefficents.

3 0
3 years ago
Read 2 more answers
Find the P-value for the indicated hypothesis test. An airline claims that the no-show rate for passengers booked on its flights
trapecia [35]

Answer:

p_v =P(z  

B. 0.2061

Step-by-step explanation:

1) Data given and notation

n=380 represent the random sample taken

X=19 represent the no-shows in the sample

\hat p=\frac{19}{380}=0.05 estimated proportion of no-shows in the sample

p_o=0.06 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the no-show rate for passengers booked on its flights is less than 6%:  

Null hypothesis:p\geq 0.06  

Alternative hypothesis:p < 0.06  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.05-0.06}{\sqrt{\frac{0.06(1-0.06)}{380}}}=-0.8208  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a one left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very high value and using the significance level for example \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of no-show rate for passengers booked on the company flights is nor significantly less than 0.06 or 6%.  

4 0
3 years ago
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