All categories

3 years ago

I need help I am lost please help me

Mathematics

1 answer:

Evgen [1.6K]3 years ago

4 0

Answer:

Step-by-step explanation:

Because 6 is 6 times as 1, 12 is 6 times as 2, 18 is 6 times as 3 and so on.

You might be interested in

Evaluate: 6-(2/3)^2 A. 17/3 B. 52/3 C. 49/9 D. 50/9

Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

....................................................................................................................................

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations! :)

$\dag\textsf{Acronym \: PEMDAS}$

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is $\mathsf{6-(\cfrac{2}{3})^2}$

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain $\mathsf{6-\cfrac{4}{9}}$ .

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: $\mathrm{\cfrac{6}{1}-\cfrac{4}{9}}$ . Now let's multiply the denominator and the numerator of the first fraction times 9: $\mathrm{\cfrac{54}{9}-\cfrac{4}{9}}$ .

See, now the fractions have the same denominator. All we should do now is subtract the numerators: $\mathrm{\cfrac{50}{9}}$ .

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

$\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star$

$\underline{\rule{300}{5}}$

5 0

2 years ago

Read 2 more answers

Which postulate can be used to prove that the triangles are congruent?

Varvara68 [4.7K]

Haven't been taught this; but from what I searched up; I think the postulate for proving these shapes' congruence is Hypotenuse/Leg. I have no exact idea however. Correct me if I'm wrong :/

5 0

3 years ago

Read 2 more answers

These are samples of student work. Both students got the same answer, but did the work differently. Which student did the work c

Alchen [17]

Answer:

Student B did the problem corectly

Step-by-step explanation:

Student a did 3*4 while student B did 3*3*3*3 which would equal 27

3 0

2 years ago

PLEASE HELP!! Algebra 2 Review !!

Kamila [148]

Answer:

$\frac{28-3i}{26}$

Step-by-step explanation:

For #2, remember that $i=\sqrt{-1}$ , so $i^{2}=-1$ Also, (a+b)(a-b), where a and b are any numbers, (a+b)(a-b)= $a^2-b^2$ . Now, to simplify, or radicalize, a number with surds in the denominator, you have to multiply the denominator by its conjugate. If there is a complex number $a+bi$ , where a and b are any numbers, the conjugate is always $a-bi$ . Lets apply these rules. The conjugate of 4+6i is 4-6i, so do this:

$\frac{5+6i}{4+6i}=\frac{(5+6i)(4-6i)}{(4+6i)(4-6i)}=\frac{20+24i-30i+36}{16+36}=\frac{56-6i}{52}=\frac{2(28-3i)}{2(26)}=\frac{28-3i}{26}$

Our answer is (28-3i)/(26)!

6 0

3 years ago

What is the interquartile range for the data set??

kramer

Answer:

Step-by-step explanation:

First, order the numbers in order. Then find the "middle numbers" and omit them after you have divided the number set into two equals parts. Then find the median of those number sets and then subtract.

You should get 71-6 at the end which is 65.

8 0

3 years ago