Create a system of linear equations that has one solution. Solve the system using substitution to prove your

Mathematics

1 answer:

bezimeni [28]2 years ago

3 0

Answer:

y = -2x + 3

y = -1/2x + 5

Step-by-step explanation:

So the best way to solve is to come up with two slopes, I'd prefer 2 perpendicular slopes because perpendicular lines only cross once hence one solution guaranteed
so say we choose a slopeA = 2 and slopeB = -1/2, the slopes are perpendicular only if when you multiply them you get -1
then we use the slope intercept form of an equation y = mx + b
we make up two equations y = -2x + b and y = -1/2x + b , now we can just make up number for b so the two equations are
y = -2x + 3
y = -1/2x + 5
Then we solve them by substituting for y so
-1/2x + 5 = -2x + 3 and x = -4/3
and then we put this to get y in either equation
y = -2(-4/3) + 3
y = 17/3
So the equations work

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· Amanda has $210 in her school lunch account. She spends $35 each week on school lunches. The

tigry1 [53]

Answer:

(See step-by-step)

Step-by-step explanation:

Let’s start by making A-(X) and W-(Y). So, when substituting the variables you get x=210-35y. When x=0, the answer to the equation is 6. So, the y-intercept (when x=0) is 6 or (0,6). When y=0, the answer to the equation/x-intercept(y=0) is 210 or (210,0). The graph itself looks like the image included.

The domain, realistically, is x>=0 however on the graph itself, the domain is x= All Real Numbers. The range realistically is y>=0, but on the graph it is also All Real Numbers.

The x-intercept is the account when no weeks have passed and no money is lost (210) and the y-intercept is the maximum amount of weeks before there is no more money in the account (6).