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Gelneren [198K]
3 years ago
10

Create a system of linear equations that has one solution. Solve the system using substitution to prove your

Mathematics
1 answer:
bezimeni [28]3 years ago
3 0

Answer:

y = -2x + 3

y = -1/2x + 5

Step-by-step explanation:

  • So the best way to solve is to come up with two slopes, I'd prefer 2 perpendicular slopes because perpendicular lines only cross once hence one solution guaranteed
  • so say we choose a slopeA = 2 and slopeB = -1/2, the slopes are perpendicular only if when you multiply them you get -1
  • then we use the slope intercept form of an equation y = mx + b
  • we make up two equations y = -2x + b and y = -1/2x + b , now we can just make up number for b so the two equations are
  • y = -2x + 3
  • y = -1/2x + 5
  • Then we solve them by substituting for y so
  • -1/2x + 5 = -2x + 3 and x = -4/3
  • and then we put this to get y in either equation
  • y = -2(-4/3) + 3
  • y = 17/3
  • So the equations work
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Guys I really need help with these too thanks u before!!!!
Natali5045456 [20]
Hey!!

here is your answer >>>

1) 3x - 10 > 11

let's take this as 3x - 10 = 11

3x = 21

x = 7
So, The numbers of X are always more than 7

2) 9x + 2 < 5

9x + 2 = 5

9x = 3

x = 1÷2

The numbers of X are always less than 1 ÷ 2

3) 2x + 8 < 6

2x + 8 = 6

2x = 2

x = 1

The numbers of X are less than 1

4) 4x - 3 < 12

4x - 3 = 12

4x = 15

x = 15 ÷ 4

The numbers of X are less than 15 ÷ 4

5) 2 ( 9 + x ) > 20

2 ( 9 + x ) = 20

9 + x = 10

x = 1

The numbers of X are more than 1

We can solve the rest using this

Hope my answer helps!
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