As is the case for any polynomial, the domain of this one is (-infinity, +infinity).
To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,
The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.
Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).
Answer:
625
Step-by-step explanation:
Answer:
20 years
Step-by-step explanation:
9000/ 100= 900 = 10%
900/2= 450
450 x 2= 900
900 x 10= 9000
Now we multiply 10 by 2 because we doubled the value of our 450 into a 900 and now we get 20.
We have to solve this quadratic equation 
for n to get <em>which figure has 56 blocks</em>.
For middle term factorization, we need <em>two numbers that multiplied gives us -56 and added gives us 1 (coefficient of n).</em>
<em>Such two numbers are </em><em>8</em><em> and </em><em>-7</em><em>. We can now write,</em>
<em>
</em>
<u><em>"There is no negative figure number possible, so we disregard -8"</em></u>
Our answer is 7.
ANSWER: The 7th figure has 56 blocks.
Set the to equal:
x^2 - 4x+4 = 2x-4
solve for X
subtract 2x from each side:
x^2 -6x + 4 = -4
subtract 4 from each side:
x^2 -6x = -8
add 8 to both sides:
x^2 -6x +8 = 0
factor the polynomial:
x = 4 and x = 2
using the line equation replace x with 2 and 4 and solve for y
y = 2(2) - 4 = 0
y = 2(4)-4 = 4
so the 2 points the line crosses the curve is (2,0) and (4,4)
using those 2 points you can calculate the length:
distance = sqrt((x2-x1)^2 +(y2-y1)^2
distance = sqrt( (4-2)^2 + (4-0)^2)
distance = sqrt (2^2 + 4^2)
distance = sqrt (4+16)
= sqrt 20
= 2 sqrt(5) EXACT LENGTH
