A linear equation has 1 for all exponents on the placeholders
aka the equation is first degree (aka the hightest exponent on placeholders=1) so
it is linear
Answer:
Point slope is ( Y+4) = 1/2(x+3)
Slope intercept is Y = 1/2(x) -5/2
Step-by-step explanation:
For the point slope form.
Given the point as (-3,-4)
And the gradient m = 1/2
Point slope form is
(Y - y1) = m(x-x1)
So
X1 = -3
Y1 = -4
(Y - y1) = m(x-x1)
(Y - (-4)) = 1/2(x -(-3))
( Y+4) = 1/2(x+3)
For the slopes intercept form
Y = mx + c
We can continue from where the point slope form stopped.
( Y+4) = 1/2(x+3)
2(y+4)= x+3
2y + 8 = x+3
2y = x+3-8
2y = x-5
Y = x/2 - 5/2
Y = 1/2(x) -5/2
Where -5/2 = c
1/2 = m
Answer:
94
Step-by-step explanation:
Since the circle equals to 142 degrees you have to subtract the already given umber (48) by the total amount and it'll give you the missing angle which is 94.
Answer:
t to the sixth power equals 9
t=1.5
Step-by-step explanation:
