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3 years ago

the following two triangles are similar. Find the missing side length represented by x. Please help i am almost done.

Mathematics

1 answer:

lbvjy [14]3 years ago

5 0

Answer:

7 inches

Step-by-step explanation:

First, you make an imbalanced equation: 22.75/x=13/4. Then you cross multiply: 22.75 * 4= 91. Then divide 91/13 = 7.

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A rectangular prism has a length of 12 inches, a width of 5 inches, and a height of 4 1/4 inches.

Darya [45]

Answer:

130.56

Step-by-step explanation:

Volume of the prism is 12×5×4.25=255 in³

Volume of the cubes are 1.25³=1.953125 in³

255/1.953125 = 130.56 in³

brainliest plz

5 0

2 years ago

What is the equation of the line that goes through the points (5, 11) and (7,21)?

iragen [17]

Answer:

y = 5x - 14

Step-by-step explanation:

First point coordinates

x₁

y₁

Second point coordinates

x₂

y₂

Result

Slope (m)

m = 10 / 2 = 5 / 1 = 5

Your function

The entered points belong to an increasing, linear function.

Equation: y = 5x - 14.

Hope i helped :)

5 0

2 years ago

You are taking a multiple-choice test that has 55 questions. each of the questions has 33 answer choices, with one correct ans

siniylev [52]

<span>Each question has 5 possible choices for an answer>
1st question: 5 ways
2nd question: 5 ways
.......
12th question: 5 ways

----
Total # of possible answers 5*5*5...*5*5 = 5^12 = 244,140,625
-----
Cheers,
Stan H.
=========================
The answer is 244,140,625</span>

5 0

2 years ago

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago

Which number has the same value as 28 tens? 28 or 280

KIM [24]

28 because we are talking about TENS meaning there can only be 2 digits

3 0

3 years ago