Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
Answer:
The measures of a pair of same-side exterior angles are 10w and 5v. ... Find the measure of angles 1-7 given that lines m and n are parallel and t is transversal. ... Solve for x. 120= 15x +5+ 22x +4. 120 = 37% +. 4. (X=3]. 6. Use the following figure, given that ... Find the measure of angle 1. m24 = 123, mZ1 = 2x, mZ2 = x +42.
Step-by-step explanation:
Answer:
The first 2
Step-by-step explanation:
First expression = -4+30-3 =23
Second expression = 8(10+4)= 112.
The others would lead to a negative number.
Remember negative times negative = positive
Negative times negative times negative = negative
Answer:
4n+6
Step-by-step explanation:
Answer:
Step-by-step explanation:
