Answer:
Step-by-step explanation:
2(x-5)+2-3(5-2x)=16
2x-10+2-15+6x =16
8x-23 =16
8x =39
x = 39/8
Answer:
Whenever I'm alone with you
You make me feel like I am home again
Whenever I'm alone with you
You make me feel like I am whole again
Whenever I'm alone with you
You make me feel like I am young again
Whenever I'm alone with you
You make me feel like I am fun again
However far away
I will always love you
However long I stay
I will always love you
Related
Whatever words I say
I will always love you
I will always love you
Whenever I'm alone with you
You make me feel like I am free again
Whenever I'm alone with you
You make me feel like I am clean again
However far away
I will always love you
However long I stay
I will always love you
Whatever words I say
I will always love you
I will always love you
However far away
I will always love you
However long I stay
I will always love you
whatever words I say
I will always love you
I'll always love you
I'll always love you
I love you
-Adele<3 You got this!
Step-by-step explanation:
Answer:
b. 21
Step-by-step explanation:
The first five mutiples of 7 are:<em> 7, 14, 21, 28, 35. </em>You can get these by multiplying 7 to any integer.
- 7x1 = 7
- 7x2 = 14
- 7x3 = 21
- 7x4 = 28
- 7x5 = 35
In order to get the average of these numbers, you have to add them and divide the sum to the total number of multiples.
Let's add first.
7+14+21+28+35 = 105
Let's divided 105 by 5, which is the number of the multiples of 7.
105÷5 = 21
<em>The answer is 21.</em>
<span>Point G cannot be a centroid because JG is shorter than GE.
Without the diagram, this problem is rather difficult. But given what a centroid is for a triangle, let's see what statements make or do not make sense. Assumptions made for this problem.
G is a point within the interior of the triangle HJK.
E is a point somewhere on the perimeter of triangle HJK and that a line passing from that point to a vertex of triangle HJK will have point G somewhere on it.
Point G cannot be a centroid because JG does not equal GE.
* If G was a centroid, then JG would not be equal to GE because if that were the case, you could construct a circle that's both tangent to all sides of the triangle while simultaneously passing through a vertex of the triangle. That's impossible, so this can't be the correct choice.
Point G cannot be a centroid because JG is shorter than GE.
* This statement would be true. So this is a good possibility as the correct answer assuming the above assumptions are correct.
Point G can be a centroid because GE and JG are in the ratio 2:1.
* There's no fixed relationship between the lengths of the radius of a circle who's center is at the centroid and the distance from that center to a vertex of the triangle. And in fact, it's highly likely that such a ratio will not even be constant within the same triangle because it will only be constant of the triangle is an equilateral triangle. So this statement is nonsense and therefore a bad choice.
Point G can be a centroid because JG + GE = JE.
* Assuming that the assumption about point E above is correct, then this relationship would hold true for ANY point E on the side of the triangle that's opposite to vertex J. And only 1 of the infinite possible points is correct for the line JE to pass through the centroid. So this is also an incorrect choice.
Since of the 4 available choices, all but one are complete and total nonsense when speaking about a centroid in a triangle, that one has to be the correct answer. So "Point G cannot be a centroid because JG is shorter than GE."</span>
Answer:
The value of 
is 2.
Step-by-step explanation:
The standard form of the equation of the line is of the form:
Where:
, 
- Independent and dependent variable, dimensionless.
- Slope, dimensionless.
- y-intercept, dimensionless.
Given that line 
is perpendicular to 
, the slope is equal to:
Where 
is the slope of the perpendicular line, dimensionless.
If 
, then:
If 
and 
, the y-intercept of the line is:
The equation of the line is 
. Given that 
and 
, the value of is:
The value of is 2.
