I'm going to assume that you meant the following:
(x-1)
---------------
x^2-3x+2
Factoring the denominator, we get:
(x-1)
------------
(x-1)(x-2)
Notice that we have x-1 in both the numerator and the denominator. This factor cancels. HOWEVER: x can still not equal 1, which would lead to div. by zero. With the factor x-1 cancelled, we have 1 / (x-2). As x approaches 1 from either side, y approaches 1 / (1-2), or 1 / (-1), or -1. Thus, the limit exists and is -1.
Answer:
x=2
Step-by-step explanation:
AB/BD=BC/BE
2/1=x/1
2=1x
x=2
(x + 4) (x + 2)
=x^2 +2x + 4x + 8
=x^2 + 6x + 8
the other factor is (x + 2)
Mot enough information given.
The rule might be
-- add 6
or
-- double and add 8
or
-- square
or
-- multiply by -2 .
We need one more term to determine what the rule is for calculating the next term from the previous one.
The
Answer:
106
Step-by-step explanation:
