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3 years ago

An increase in the atomic number________the atomic radius moving from left to right across a period.

Chemistry

1 answer:

frez [133]3 years ago

4 0

Answer:

decrease

Explanation:

Atomic radius :

It is the distance from the center of nucleus to the outer most electronic shell.

Trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required

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What is the elements don’t bond with other elements because their outer shell is filled?

Shtirlitz [24]

Answer:

Inert gases or noble gases

Explanation:

These gases have 8 outer shells meaning their full so they won't allow chemical reactions therefore providing an inert environment hence the name inert gas.

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3 years ago

At a certain concentration of H2 and I2, the initial rate of reaction is 4.0 x 104 M / s. What would the initial rate of the rea

andreev551 [17]

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

$rate=k[H_2]^2[I_2]^2$

At a certain concentration of $H_2$ and $I_2$ , the initial rate of reaction is 4.0 × 10⁴ M/s. What would the initial rate of the reaction be if the concentration of

Answer : The initial rate of the reaction will be, $1.0\times 10^4M/s$

Explanation :

Rate law expression for the reaction:

$rate=k[H_2]^2[I_2]^2$

As we are given that:

Initial rate = 4.0 × 10⁴ M/s

Expression for rate law for first observation:

$4.0\times 10^4=k[H_2]^2[I_2]^2$ ....(1)

Expression for rate law for second observation:

$R=k(\frac{[H_2]}{2})^2[I_2]^2$ ....(2)

Dividing 2 by 1, we get:

$\frac{R}{4.0\times 10^4}=\frac{k(\frac{[H_2]}{2})^2[I_2]^2}{k[H_2]^2[I_2]^2}$

$\frac{R}{4.0\times 10^4}=\frac{1}{4}$

$R=1.0\times 10^4M/s$

Therefore, the initial rate of the reaction will be, $1.0\times 10^4M/s$

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3 years ago

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Please explain in more detail

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3 years ago

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Anastaziya [24]

Answer:

Diazanium sulfate is the correct answer.

Explanation:

Hope this helped Mark BRAINLIEST!!

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3 years ago

What happens to the amplitude of waves when two waves overlap and are out of phase with each other?

11Alexandr11 [23.1K]

Answer:

Also called superposition. When overlapping waves produce a wave with an amplitude that is the sum of the individual waves. When overlapping waves produce a wave with an amplitude that is less than the sum of the individual waves.

Explanation:

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3 years ago