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Diano4ka-milaya [45]
3 years ago
6

What are the 10 physical properties?

Chemistry
1 answer:
vekshin13 years ago
8 0
Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity. We can observe some physical properties, such as density and color, without changing the physical state of the matter observed<span>.</span>
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Do guitar strings deform? and how??
galina1969 [7]

Answer:

yes; and because of how roughly they are played.

Explanation:

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A mixture of lipids is applied to a silica gel column, and the column is then washed with increasingly polar solvents. the mixtu
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Which tool is used to measure mass?
kherson [118]

Answer: c. balance

Explanation: Mass is the amount of matter contained in a body.

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3 years ago
Read 2 more answers
The standard free energy of activation of one reaction A is 95.00 kJ mol–1 (22.71 kcal mol–1). The standard free energy of activ
diamong [38]

Answer:

The answer to the questions are as follows

Reaction B is 4426.28 times faster than reaction A

(b) Reaction B is faster.

Explanation:

To solve the question we are meant to compare both reactions to see which one is faster

The values of the given activation energies are as follows

For A

Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and

for  B

Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)

T is the same for both reactions and is equal to 298 k

Concentration of both reaction = 1M

The Arrhenius Law is given by

k = Ae^{\frac{-E_{a} }{RT} }

Where

k = rate constant

Ea = activation energy

R = universal gas constant

T = temperature  (Kelvin )

A = Arrhenius factor

Therefore

For reaction A, the rate constant k₁ is given by k₁ = Ae^{\frac{-95000}{(8.314)(298)} }

And for B the rate constant k₂ is given by k₂ = Ae^{\frac{-74200 }{(8.314)(298)} }

k₁ = A×2.225×10⁻¹⁷

k₂ = A×9.850×10⁻¹⁴

As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times

3 0
3 years ago
At STP, 2.24 L of carbon dioxide gas is collected. What is the number of molecules of gas present in this volume?
Doss [256]

Considering the definition of STP conditions and Avogadro's number, the number of molecules of gas present in 2.24 L is 6.023×10²² molecules.

<h3>Definition of STP condition</h3>

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

<h3>Definition of Avogadro's number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Amount of molecules of carbon dioxide gas</h3>

At STP, 2.24 L of carbon dioxide gas is collected. So, you can apply the following rule of three: if by definition of STP conditions 22.4 L are occupied by 1 mole of carbon dioxide gas, 2.24 L are occupied by how many moles of carbon dioxide gas?

amount of moles of carbon dioxide gas=\frac{2.24 Lx1 mole}{22.4 L}

amount of moles of carbon dioxide gas= 0.1 moles

Finally, 0.1 moles of carbon dioxide gas are collected.

Then you can apply the following rule of three, considering the Avogadro's number:  If 1 mole of carbon dioxide gas contains 6.023×10²³  molecules, 0.1 mole of carbon dioxide gas contains how many molecules?

amount of molecules of carbon dioxide gas= (6.023×10²³ molecules × 0.1 moles)÷1 mole

amount of molecules of carbon dioxide gas=6.023×10²² molecules

Finally, the number of molecules of gas present in 2.24 L is 6.023×10²² molecules.

Learn more about

STP conditions:

brainly.com/question/26364483

brainly.com/question/8846039

brainly.com/question/1186356

Avogadro's Number:

brainly.com/question/11907018

brainly.com/question/1445383

brainly.com/question/1528951

#SPJ1

8 0
2 years ago
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