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PtichkaEL [24]
3 years ago
15

Lizzy bought 5 yards of fabric to make

Mathematics
1 answer:
inn [45]3 years ago
6 0

Answer:

180 hope that helps :) jdojod

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You clean a community park for 6.5 hours. You earn $42.25. How much do you earn per hour
kvv77 [185]

Well you divide $42.25 by 6.5 and you’ll get your hourly pay which is $6.25

4 0
3 years ago
Read 2 more answers
Which is a factor of 144 − 49x2?<br><br> 12 - 7x2<br> 72 – 7x2<br> 12 – 7x<br> 72 + 7x
Vinil7 [7]

Answer:

(12-7x)

Step-by-step explanation:

144 − 49x²

by observation, we can see that 144 = 12² and 49 = 7²

hence we can rewrite the equation

144 − 49x²

= 12² - 7²x²

= 12² - (7x)²

recall that the expression x² - y² = (x+y)(x-y)

hence,

12² - (7x)²

= (12 + 7x)(12-7x)

(12-7x) appears in the expression above, hence 12 -7x is a factor

5 0
3 years ago
Read 2 more answers
Pls help im really dum
Naddik [55]

Answer:

1: h0m0zyg0us

2: 75%

3: 50%

Step-by-step explanation:

i think im not sure

8 0
3 years ago
What would be the answer for 16.058-1.2, and how would you solve it. Please and thankyou.
Annette [7]

Answer:

14.858

Step-by-step explanation:

16.058−1.2

=16.058−1.2

=16.058+−1.2

=14.858

7 0
3 years ago
Read 2 more answers
A computer maker receives parts from three suppliers, S1, S2, and S3. Fifty percent come from S1, twenty percent from S2, and th
rewona [7]

Answer:

a) 4.9 % of all parts is defective or 0.049 of the total parts.

b)  0.5102 is the probability that the defective part was supplied by S1

Step-by-step explanation:

N is the total number of parts from supplier S1, S2 and S3.

N1 = 0.5*N is the total number of part supplied by S1

N2 = 0.2*N is the total number of part supplied by S2  

N3 = 0.3*N is the total number of part supplied by S3

a) if Nd1 is the number of defective parts from supplier S1, Nd2 is the number of defective parts from supplier S2 and Nd3 is the number of defective parts from supplier S3, the the total defective parts Nd is:

Nd = Nd1 + Nd2 + Nd3, where

Nd1 = 0.05*N1 = 0.05*0.5*N = 0.025*N,

Nd2 = 0.03*N2 = 0.03*0.2*N = 0.006*N,

Nd3 = 0.06*N3 = 0.06*0.3*N = 0.018*N,

Then Nd = Nd1 + Nd2 + Nd3 =  0.049*N, so Nd/N = 0.049

b) P(S1 \vert d) = \frac{P(S1,d)}{P(d)} = \frac{P(d \vert S1)}{P(d)} = \frac{0.05*0.5}{0.049} \approx 0.5102

for the last expression I used the Bayes tehorem.

P(S1 \vert d) is the probability that occur S1 given that d (defective) is true. This a conditional probability.

see at https://en.wikipedia.org/wiki/Bayes%27_theorem

6 0
3 years ago
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