Answer:
А.The system has two solutions, but only one is viable because the other results in a negative width.
Step-by-step explanation:
Given
Let:
length of play area A
width of play area A
length of play area B
width of play area B
Area of A
Area of B
From the question, we have the following:




The area of A is:

This gives:

Open bracket

The area of B is:


Substitute: 

Open brackets


Expand


We have that:

This gives:

Collect like terms


Using quadratic calculator, we have:
or
--- approximated
But the width can not be negative; So:

Answer:
The answer is the top right one since the total $96.35 is on the deposit side.
( i did this before and got it right btw)
Answer: we can get the sequence of reasons with help of below explanation.
Step-by-step explanation:
Here It is given that, line segment BD is the perpendicular bisector of line segment AC. ( shown in below diagram)
By joining points B with A and B with C ( Construction)
We get two triangles ABD and CBD.
We have to prove that : Δ ABD ≅ Δ CBD
Statement Reason
1. AD ≅ DC 1. By the property of segment bisector
2. ∠BDA ≅ ∠ BDC 2. Right angles
3. BD ≅ BD 3. Reflexive
4. Δ ABD ≅ Δ CBD 4. By SAS postulate of congruence
The first quartile of the data set is 28 because it is the median of the lower set.
Answer:
-32x+26
Step-by-step explanation: