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3 years ago

There are 234 students in 9 different classrooms. What is the ratio of students to classrooms?

Mathematics

2 answers:

Lina20 [59]3 years ago

6 0

Answer:

26 students in each classroom

Step-by-step explanation:

234/9=26

Paraphin [41]3 years ago

5 0

Answer:

234 to 9

Step-by-step explanation:

If the ratio is students to classrooms that means students comes first in the ratio. In this case it would be 234 and 9 for the classrooms.

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The speed of sound in air on a certain stormy day is about 1130 feet per second. You see a flash of lightning striking some dist

Elina [12.6K]

Answer:

distance = 1.5 miles(approx.)

Step-by-step explanation:

given,

speed of sound = 1130 ft/s

1 ft = 0.3048

1130 ft/s = 0.3048 × 1130 m/s

= 344.424 m/s

time = 7 second

distance = speed × time

distance = 344.424 × 7

distance = 2410.968 m

1 m = 0.0006214 miles

2410.968 m = (0.0006214 × 2410.968) miles

distance = 1.498 miles

distance = 1.5 miles(approx.)

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3 years ago

CAN SOMEONE PLEASE HELP ME ASAP PLEASEEEE!!!

oee [108]

Could be wrong but since given the smaller quadrilateral is similar to to larger one, by definition the ratio of there corresponding sides would be congruent. Length of 5 of ec is to 10 of bc as the length of fe (6) is to the length of ab would be 12

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3 years ago

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algol [13]

Answer:

translate

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A, B, and C are collinear. True or False?

Dafna1 [17]

Answer:

It is false. Just look at the face of the shape.

Step-by-step explanation:

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3 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago