1st quartile: 11
median: 38.50000
3rd quartile: 45
<h3>According to the given information:</h3>
- Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
- There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
- 6,7,15,36, or the left-most half of the data, make up the sample.
- The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
- 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
- The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
- The biggest value deviates 10.5 from the median (49-38.5)
Measure descriptive statistics
1st quartile: 11
median: 38.50000
3rd quartile: 45
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I understand that the question you are looking for is :
2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45
X=7.5 area= 42
You know that the total perimeter is 39 so to find x you need to add what you already have. You’ll find there are 3 sides you don’t know the length of and all you have to do is find the shorter one which is basically 9-7=2 then add everything together and subtract it from 39 then divide it by 2 to find the two sides left
El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.
<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>
En esta pregunta debemos encontrar el volumen <em>remanente</em> entre el espacio de una caja <em>cúbica</em> y una esfera introducida en el elemento anterior. El volumen <em>remanente</em> es igual a sustraer el volumen de la pelota del volumen de la caja.
Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:
Cubo
V = l³
V = (4 cm)³
V = 64 cm³
Esfera
V' = (4π / 3) · R³
V' = (4π / 3) · (2 cm)³
V' ≈ 33.5103 cm³
Segundo, determinamos la diferencia de volumen entre los dos elementos:
V'' = V - V'
V'' = 64 cm³ - 33.5103 cm³
V'' = 30.4897 cm³
El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.
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Answer:
√26 ≈ 5.1 units
Step-by-step explanation:
√(x₂ - x₁)² + (y₂ - y₁)²
√(3/2 - 5/2)² + (8 - 3)²
√(-1)² + (5)²
√1 + 25
√26
1,000,000,000,000 is the answer
