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3 years ago

N the figure, m || n and x || y. If the m /_15 = 75, find m /_1 .

Mathematics

1 answer:

uranmaximum [27]3 years ago

7 0

Answer:

105°

Step-by-step explanation:

m(15) = 75°

Also it's given that m||n . So taking y as transversal ,

m(15) = m(13) = 75°

Also it's given that x||y . So taking m as transversal ,

m(13) = m(5) = 75°

Now m(5) & m(1) are linear pair. So ,

m(5) + m(1) = 180°

=> 75° + m(1) = 180°

=> m(1) = 180° - 75°

= 105°

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Answer:

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

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In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In the study 340 babies were born, and 289 of them were girls. This means that $n = 340, \pi = \frac{289}{340} = 0.85$

Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born.

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $z = 2.575$ .

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$\pi - z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 - 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.80$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 + 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.90$

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b)Yes, the proportion of girls is significantly different from 0.5.

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