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3 years ago

I WILL MARK YOU TOP IF YOU HELP ME I NEED THIS ASAP!!!!

1 answer:

6 0

The basketballs and racquetball eventually stopped bouncing due to the first law. the first law states that an object at rest will stay at rest unless acted upon by an external force. this means that once the 2 balls lose friction, they will remain at rest until acted upon by an external force. once the 2 balls lose friction(energy), they come to a complete stop.

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A) State what is meant by absolute zero temperature.

Lynna [10]

Answer:

Absolute zero temperature is the lowest limit of the thermodynamic temperature scale, a state at which the enthalpy and entropy of a cooled ideal gas reach their minimum value, taken as zero kelvins.

3 0

3 years ago

39. Draw a complete free body diagram of a 40 kg plastic crate at rest on a wooden table (us=0.7). The applied force to the righ

Leya [2.2K]

In order to draw the free body diagram, first let's calculate the friction force acting on the crate:

$\begin{gathered} F_f=N\cdot\mu \\ F_f=40\cdot9.8\cdot0.7 \\ F_f=274.4\text{ N} \end{gathered}$

Since the friction force is greater than the force applied, the crate will not move, and the friction force will be equal to the force applied.

The weight force is equal to 40 * 9.8 = 392 N.

So, drawing the diagram, we have:

4 0

2 years ago

Calcite (CaCO_3) is a crystal with abnormally large birefringence. The index of refraction for light with electric field paralle

katrin2010 [14]

Answer:

(a) 42.28°

(b) 37.08°

Explanation:

From the principle of refraction of light, when light wave travels from one medium to another medium, we have:

$\frac{n_{b} }{n_{a} }$ = sinθ $_{a}$ /sinθ $_{b}$

In the given problem, we are given the refractive indices of light which are parallel and perpendicular to the axis of the optical lens as 1.4864 and 1.6584 respectively.

For critical angle θ $_{a}$ = θ $_{c}$ , θ $_{b}$ = 90°; $n_{b} = 1$

(a) $n_{a} = 1.4864$

$\frac{1 }{1.4864 }$ = sinθ $_{c}$ /sin90°

0.6728 = sinθ $_{c}θ[tex]_{c} = sin^(-1) 0.6728 = 42.28°(b) [tex]n_{a} = 1.6584$

$\frac{1 }{1.6584}$ = sinθ $_{c}$ /sin90°

0.60299 = sinθ[tex]_{c}

θ[tex]_{c} = sin^(-1) 0.60299 = 37.08°

7 0

4 years ago

To understand the nature of electric fields and how to draw field lines. Electric field lines are a tool used to visualize elect

Brrunno [24]

Explanation:

The electric field is defined as the change in the properties of space caused by the existence of a positively (+) or negatively (-) charged particle. The electric field can be represented by infinitely many lines from a particle, and those lines never intersect each other. Depending on the type of charge we can see different cases:

Let's say we have a positive charge alone (image 1). The field lines are drawn from the centre of the particle outwards to infinity (in other words, they disappear from the edge of the picture). Meaning the direction of the electric field points outwards the particle.

For a negative charge alone (image 2), the lines come from infinity to the centre, and point towards the particle (i.e. lines appear from the edge of the picture).

Let's see what happens if we have two charges together:

Two positive charges (image 3): Since the charges are of the same type (positive), the particles repel each other. Then the field lines will avoid each other so they do not join. The charge is positive, so lines point outwards.
Two negative charges (image 4): Again, the charges are both negative, so they repel. But they are negative, so the field points inwards.
Negative and positive charges (image 5): They are different charges, so the force between them is attractive. This causes the field lines from both to join. They go out of the positive and come into the negative particle.

Image 6:

The lines are passing through infinite points of the space. If we choose a certain point and measure the electric field, we can see to which direction the electric field points. This is the direction of the electric field vector. It does not matter which point we choose; the electric field vector touches the field line only at this point, which means it is tangent to the field line.

7 0

3 years ago

Engineers can determine properties of a structure that is modeled as a damped spring oscillator, such as a bridge, by applying a

Kazeer [188]

The value of spring constant and the oscillator's damping constant is

K= 6605.667008, b= 0.002884387

Explanation:

For Weakly damping spring oscillator

K/m = W_0^2 (at resonance)

K= mW_0^2

=0.206 * ( 2π * 28.5) ^2

=0.206 * (2π)^2 * (28.5)^2

K= 6605.667008

F = - bV

b= -F/V = -F/ -W_0 * m

=F/W_0 * m

= 0.438N / 2π * 28.5 * 0.848

b= 0.002884387

8 0

3 years ago