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3 years ago

I WILL MARK YOU TOP IF YOU HELP ME I NEED THIS ASAP!!!!

1 answer:

6 0

The basketballs and racquetball eventually stopped bouncing due to the first law. the first law states that an object at rest will stay at rest unless acted upon by an external force. this means that once the 2 balls lose friction, they will remain at rest until acted upon by an external force. once the 2 balls lose friction(energy), they come to a complete stop.

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Object A has a length of 3 cm, a width of 2 cm, and a height of 4 cm. Object B is dropped into a graduated cylinder. It displace

MA_775_DIABLO [31]

Answer:

A: greater than the volume of object B

Explanation:

Based on the dimensions, the volume of object A is ...

(3 cm)(2 cm)(4 cm) = 24 cm³ = 24 mL

If object B displaces 19 mL of water, we presume that is its volume. Since 24 mL is more than 19 mL, we conclude ...

The volume of object A is greater than the volume of object B.

_____

<em>Comment on density</em>

We have presumed that object B is completely submerged. If it is not, then the relative volumes will depend on the densities. If the density of object B is less than about (19/24) g/mL, its volume may very well be larger than that of object A.

4 0

4 years ago

Select the correct answer.

Aloiza [94]

Answer:

Explanation:

7 0

3 years ago

A woman stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.90

kiruha [24]

Answer:

1 m/s² down

Explanation:

"Calculate the acceleration of the elevator, and find the direction of acceleration."

Sum of forces in the +y direction:

∑F = ma

N − mg = ma

0.9 mg − mg = ma

-0.1 mg = ma

a = -0.1 g

a = -1 m/s²

6 0

3 years ago

A race car starting from rest accelerates uniformly at a rate of 4.90 meters per squared. What is the cars speed after it has tr

shusha [124]

Ok, we need to find a relation for the speed as it relates to the acceleration. This is given by the integral of acceleration:

$v= \int\limits^{t}_{0} {a} \, dt' =at$

Where we have the initial velocity is 0m/s and a will be 4.90m/s².

But we see there is an issue now... We know the velocity as a function of time, but we don't know how long the car has been accelerating! We need to calculate this time by now finding the position function as a function of time. This way we can solve for the time, t, that it takes to go 200m accelerating this way and then substitute that time into our velocity equation and get the velocity.
Position is just the integral of velocity:

$s= \int\limits^{}_{} {at} \, dt = \frac{1}{2}at^2$

Where the initial velocity and initial position are both zero.

Now we set this position function equal to 200m and find the time, t, it took to get there

$\frac{1}{2}(a \frac{m}{s^2} )t^2=200m \\ \\ \frac{1}{2}4.90 \frac{m}{s^2} t^2=200m \\ \\ t^2= \frac{400m}{4.90 \frac{m}{s^2}}=81.63s^2 \\ \\ t= \sqrt{81.63s^2 } =9.04s$

Now let's put t=9.04s into our velocity equation:

$v =at=4.9\frac{m}{s^2} \times 9.04s=44.3 \frac{m}{s}$

8 0

3 years ago

So Can Someone Help Me Please Asap!!!!!!!!!!!!!!!!!!!!!!!

eimsori [14]

Answer:

The Laws of Badminton

A match consists of the best of 3 games of 21 points.

Every time there is a serve – there is a point scored.

The side winning a rally adds a point to its score.

At 20 all, the side which gains a 2 point lead first, wins that game.

At 29 all, the side scoring the 30th point, wins that game.

3 0

3 years ago