Answer:
A. Bias
Explanation:
If the scientist was bias the results would be inaccurate and heavily one-sided.
Answer:
Explanation:
Given:
Length of a rope,
Position of Canary on the rope from one end, 
Position of Grackle on the rope from another end, 
Tension in the rope, 
linear mass distribution on the rope, 
We have for the speed of wave on the string:
<em>For canary to be undisturbed we need a node at this location.</em>
<em>Also, at the end close to Canary there must be a node to avoid any change in pattern of vibration.</em>
So,
the distance between Canary and the closer end must be equal to half the wavelength.
∴Wavelength of wave to be produced = 20 m. This will give us nodes at the multiples of 10 and anti-nodes at the multiples of 5.
Now, frequency:
Answer:
Explanation:
STEP 1
<u>Given</u>
Radius of cylinder = r = 25cm, 2.5m
mass = 27kg
cylinder is mounted so as to rotate freely about a horizontal axis that is parallel to and 60cm to the central logitudinal axis of the cylinder
height = 0.6m
<u>part 1</u>
The cylinder is mounted so as to rotate freely about a horizontal axis tha is paralle to 60cm from the central longitudinal axis of then cylinder. The rotational inertia of the cylinder about the axis of rotation is given by
<em>I = Icm + mh²</em>
<em>∴ I = 1/2mr² + mh² = 1/2x27x (0.5)² + 20 x (0.6)²</em>
<em>I=13.09kg.m²</em>
where
<em>I</em>cm is the rotational inertia of the cylinder about its central axis
m is the mass of the cylinder
h is the distance between the axis of the rotation and the central axis of the cylinder
r is the radius of the cylinder
<em> </em><em> I=13.09kg.m²</em>
<em>part2</em>
<em>from the conservation of the total mechanical energy of the meter stick, the change in gravitational potential energyof the meter stick plus the change in kinetic energy must be zero</em>
<em>Δk + Δu = 0</em>
<em>1/2 </em>I(w²-w²) = Ui-Uf
1/2 x 13.09w² = mgh
∴w=√20 x 9.8 x 0.6/(1/2 x 13.09) =117.6/6.5
w=18.09rad/s
Answer:
I think it may be decreased, but i'm in 6th grade so-
Explanation:
<h3>b. ML </h3><h3>c. M</h3><h3>d. Kg</h3>
<h3>Hope it helps...</h3>
