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SVEN [57.7K]
2 years ago
13

3. What is the gravitational force between a 70 kg physics student and her 1 kg textbook, at a distance of 1 meter? (This number

will be very small!)Object 1 (m): 70 kg studentObject 2 (m2): 1 kg textbookDistance: (r): 1 meter
Physics
1 answer:
Rina8888 [55]2 years ago
6 0

ANSWER

\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}

EXPLANATION

Parameters given:

Mass of the student, M = 70 kg

Mass of the textbook, m = 1 kg

Distance, r = 1 m

To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:

F=\frac{GMm}{r^2}

where G = gravitational constant

Therefore, the gravitational force acting between the student and the textbook is:

\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\  \\ F=4.67*10^{-9}\text{ }N \end{gathered}

That is the answer.

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Describe effective communication strategies for gathering information, educating patients
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Explanation:

Effective communication with patients will enable one to know the needs of the patient better as well as reducing the barriers to understanding each other for both parties.

To be an effective communicator while educating patients, the person must:

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3 years ago
Match each scientist with his major discovery or contribution. 1. Ernest Rutherford discovery of the electron 2. James Chadwick
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1. Ernerst Rutherford =====> Discovery of Atomic Nucleus

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3 years ago
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The gravitational force acting on various masses is measured on different planets. Measured values for the forces acting on the
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we Know that gravitational field strength(g) at a point on a planet  is equal to  gravitational force exerted per unit mass placed at that point.

It Means,

g=F/m

Here,

g=gravitational field strength

F=Gravitational force

m=Mass

Case A

planet force =10 and mass= .5

g1=F/m

g1=10/.5

=100/5

g1=20m/s

case B

F=30 and m=2

therefore g2=30/2

g2=15m/s^2

case C

F=45 and m=3

g3=45/3

=15m/s^2

case D

g4=60/6

g4=10m/s^2

from above results it is clear that the gravitational field strength of planet D is minimum which is 10m/s^2 and gravitational field strength of planet A is maximum which is 20m/s^2

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4 years ago
A particular motor can provide a maximum torque of 110 n • m. assuming that all of this torque is used to accelerate a solid, un
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Using the rotational equivalent of force:

Which is T = I*Alpha

Where: T is torque, I is the moment of inertia and Alpha is the angular acceleration. 

This is for the flywheel: J = 1/2mr^2 = 5*3^2 = 45 kgm^2 


From the equation: 


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4 years ago
A 77.0 kg rider sitting on a 7.3 kg bike is riding along at 9.3 m/s in the positive direction. The rider drags a foot on the gro
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Answer with Explanation:

We are given that

Mass of rider=m=77 kg

Mass of bike =m'=7.3 kg

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Total mass,M=m+m'=77+7.3=84.3 kg

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B.Impulse=Ft=Change in momentum=-278.19kg m/s

C.Time,t=13.2 s

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a=-\frac{3.3}{13.2}=-0.25 ms^{-2}

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