<h2>Answer:</h2>
The diagram is not showing the second law of thermodynamics. It is the demonstration of 1st law of thermodynamics.
<h3>Explanation:</h3>
Second law of thermodynamics describes the entropy of the system increase with time, it does not decrease with time. It is constant for ideal systems.
While in first law of thermodynamics, it is stated that the energy of a system can not be lost but it is transferred from one form to other form.
And in this picture, it is shown that the energy released from heat source to cold sink is used in doing work.
Work and heat are forms of energy.
Answer:
75 W
Explanation:
= temperature of the filament = 2100 K
= Emitting area of the filament = 1 cm² = 10⁻⁴ m²
= Emissivity = 0.68
= Stefan's constant = 5.67 x 10⁻⁸ Wm⁻²K⁻⁴
Using Stefan's law, Power output of the light bulb is given as
![P = \sigma e AT^{4} \\P = (5.67\times10^{-8}) (0.68) (10^{-4}) (2100)^{4}\\P = 75 W](https://tex.z-dn.net/?f=P%20%3D%20%5Csigma%20e%20AT%5E%7B4%7D%20%5C%5CP%20%3D%20%285.67%5Ctimes10%5E%7B-8%7D%29%20%280.68%29%20%2810%5E%7B-4%7D%29%20%282100%29%5E%7B4%7D%5C%5CP%20%3D%2075%20W)
Answer:
10.58 ft
Explanation:
Force, F = 1.4 N
Diameter of membrane = 7.4 mm
radius of membrane, r = 7.4 / 2 = 3.7 mm = 3.7 x 10^-3 m
Area, A = 3.14 x (3.7 x 10^-3)^2 = 4.3 x 10^-5 m^2
Density, d = 1.03 x 10^3 kg/m^3
Pressure at depth, P = h x d x g
Let h be the depth.
Pressure = force / Area
h x 1.03 x 10^3 x 9.8 = 1.4 / (4.3 x 10^-5)
h = 3.225 m = 10.58 ft
Thus, the depth of water is 10.58 ft.
The subscript for nitrogen in hydrazine, N2H4 is 2.
In chemistry, when writing the chemical formula of chemical compounds, subscripts refers to the numerical numbers that are sometimes put at the base of some chemical symbols. The subscripts are used to indicate the number of atoms that are present in each element. For example, in hydrazine, the subscript 2 indicates that two atoms of nitrogen are present, while the subscript 4 indicates that four atoms of hydrogen are presents.
The value of γ needed for transformation between the two frames is 2.2942.
To transform the position, time, mass from one coordinate frame to another frame which moves with a speed v relative to the first, we need to calculate the Lorentz constant γ .
This is given by,
![\gamma=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}](https://tex.z-dn.net/?f=%20%5Cgamma%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D%7D%20%20%20%20)
Substitute
for v and
for <em>c</em>.
![\gamma =\frac{1}{\sqrt{1-\frac{v^2}{c^2}}} \\ =\frac{1}{\sqrt{1-\frac{(2.70*10^8 m/s)^2}{(3.00*10^8 m/s)^2}}} \\ =\frac{1}{\sqrt{0.19}} \\ =2.2942](https://tex.z-dn.net/?f=%20%5Cgamma%20%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D%7D%20%20%20%5C%5C%20%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%5Cfrac%7B%282.70%2A10%5E8%20m%2Fs%29%5E2%7D%7B%283.00%2A10%5E8%20m%2Fs%29%5E2%7D%7D%7D%20%20%20%5C%5C%20%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B0.19%7D%7D%20%20%5C%5C%20%3D2.2942%20)
The Lorentz factor needed for transforming the position and time coordinates from the given frame to the frame moving with a speed v relative to it is 2.2942